Python unhexlify 十六进制到 alpha 转换失败

Question

所以我使用 this SO answer 中的代码创建2路字母数字加密函数。

基本上，函数如下所示:

from Crypto import Random
from Crypto.Cipher import AES

from binascii import hexlify
from binascii import unhexlify

def encrypt_password(self, password):
    key = current_app.config['VAULT_KEY']
    iv = Random.new().read(AES.block_size)
    cipher = AES.new(key.strip("\'"), AES.MODE_CFB, iv)
    self.password_encrypted = hexlify(iv + cipher.encrypt(password))

def decrypt_password(self):
    key = current_app.config['VAULT_KEY']
    encrypted = unhexlify(self.password_encrypted)
    cipher = AES.new(key.strip("\'"), AES.MODE_CFB, encrypted[:AES.block_size])
    return cipher.decrypt(encrypted)[AES.block_size:]

这些函数与保存encrypt_password结果的数据库对象交互；要解密，请使用decrypt_password。 (非常不言自明。)

我被困在这条线上:

encrypted = unhexlify(self.password_encrypted)

不知何故，Python 不断告诉我 self.password_encrypted 不是十六进制数字。我不知道发生了什么，因为它被作为十六进制数字保存到对象中。

顺便说一句，字符串表示形式是:'\x[decimalnumbers]'，我也认为这很奇怪。不应该是十六进制数字吗？

回溯如下:

Traceback (most recent call last):
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 2000, in __call__
    return self.wsgi_app(environ, start_response)
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1991, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1567, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/<>/venv/lib/python3.5/site-packages/flask/_compat.py", line 33, in reraise
    raise value
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1988, in wsgi_app
    response = self.full_dispatch_request()
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1641, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1544, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/<>/venv/lib/python3.5/site-packages/flask/_compat.py", line 33, in reraise
    raise value
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1639, in full_dispatch_request
    rv = self.dispatch_request()
  File "/<>/venv/lib/python3.5/site-packages/flask/app.py", line 1625, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/<>/app/public/views.py", line 64, in test_queue
    return u.decrypt_password()
  File "/<>/app/models.py", line 80, in decrypt_password
    encrypted = unhexlify(self.password_encrypted)
binascii.Error: Non-hexadecimal digit found

Answer 1

好的，我对您发布的文件做了一些修改...

 from Crypto import Random
 from Crypto.Cipher import AES 

 from binascii import hexlify, unhexlify

 import hashlib 
 from sys import stdout as puts

 class AESCipher:

      def __init__(self, key):
           self.key = key

      def encrypt_password(self, password):
         iv = Random.new().read(AES.block_size)
         cipher = AES.new(self.key, AES.MODE_CFB, iv)
         self.password_encrypted = hexlify(iv + cipher.encrypt(password))
         return self.password_encrypted

      def decrypt_password(self):
          decrypted = unhexlify(self.password_encrypted)
          cipher = AES.new(self.key, AES.MODE_CFB, decrypted[:AES.block_size])
          return cipher.decrypt(decrypted)[AES.block_size:]


#############################################################################
               """sample purposes only"""

"""Here's an example, you don't have to use stdout or the block size for encyrption 
   I decided to use the regular base 16 block size and for 'puts' I came from a 
   ruby background"""

retrive_password = AESCipher(hashlib.sha256("mylittlepony").digest())

puts.write(("\n"*3) + retrieve_password.encrypt_password("agenericpassword") + ("\n" *3))

puts.flush()

puts.write(retrive_password.decrypt_password() + ("\n" *3))

puts.flush(()

它可能与您的环境键变量有关，请确保它符合 16、24 或 32 字节构造。为 AES 初始化第一个参数。

至于'\x{0-9a-fA-f}{0-9a-fA-f}'格式，据我了解这是字符串格式的十六进制输出