c# - 如何使用 C# Complex 将矩形形式转换为极坐标形式

Question

尝试将一个数从直角坐标转换为极坐标，即从 20+j25 到 32<38.66

这是我目前所拥有的:

    static void Main(string[] args)
    {
        Complex A = new Complex (0.4, 0.3);
        Complex B = new Complex (0.6, 0.7);
        Complex C = new Complex (24, 19);
        Complex D = A + B + C;

        Console.WriteLine (D);

        Console.ReadLine();
    }

这给了我答案 20, 25.，它是矩形的。我将如何制作这个极地？

谢谢

编辑:好的，我做了一些更改，但仍然无法得到正确的答案。使用代码:

    static void Main(string[] args)
    {
        Complex RA = new Complex(25, 20);
        Console.WriteLine("{0} + i{1}", RA.Real, RA.Imaginary);

        double r, q;
        r = Math.Sqrt((RA.Real * RA.Real) + (RA.Imaginary * RA.Imaginary));
        q = Math.Atan(RA.Imaginary/RA.Real);
        Console.WriteLine("{0} < {1}", r, q);
        Console.ReadLine();
    }

我得到 32 < 0.647...答案应该是 32<38.66。谁能解释为什么我得到错误的角度？谢谢

Answer 1

明白了。必须将弧度转换为度数。感谢大家的帮助!

    static void Main(string[] args)
    {
        Complex RA = new Complex(25, 20);
        Console.WriteLine("{0} + i{1}", RA.Real, RA.Imaginary);

        double r, q, z;
        r = Math.Sqrt((RA.Real * RA.Real) + (RA.Imaginary * RA.Imaginary));
        q = Math.Atan(RA.Imaginary/RA.Real);
        z = (q * (180/Math.PI));
        Console.WriteLine("{0} < {1}", r, z);
        Console.ReadLine();
    }