python - 向脚本添加 while 循环会导致输入错误

Question

我正在编写一些代码来玩 Hangman (Python 3.5.2)。我不希望我的代码永远运行，例如 while 1 < 2: ，但我开始在没有 while 的情况下正常工作的语句上出现语法错误。 。这是我的代码:

with open('dictionary.txt') as f:
  words = f.read().splitlines()
alphabet = 'abcdefghijklmnopqrstuvwxyz'
words2 = ''
alphabetCount = []
guesses = []
input = input('Input: ')
for x in range(0, len(words)):
  valid = True
  if len(input) == len(words[x]):
    for y in range(-1, len(input)-1):
      if input[y] != words[x][y] and input[y] != '_':
        valid = False
    if valid:
      words2 = words2 + (words[x])
for x in range(0, 26):
  alphabetCount.append(0)
for x in range(0, len(words2)):
  alphabetCount[alphabet.index(words2[x])] = alphabetCount[alphabet.index(words2[x])] + 1
for z in range(0, 26):
  if max(alphabetCount) != 0 and (alphabet[alphabetCount.index(max(alphabetCount))]) not in input:
    guesses.append(alphabet[alphabetCount.index(max(alphabetCount))])
  alphabetCount[alphabetCount.index(max(alphabetCount))] = 0
print (guesses)

本质上，我想像这样循环它:

while 1 < 2:
  with open('dictionary.txt') as f:
    words = f.read().splitlines()
  alphabet = 'abcdefghijklmnopqrstuvwxyz'
  words2 = ''
  alphabetCount = []
  guesses = []
  input = input('Input: ')
  for x in range(0, len(words)):
    valid = True
    if len(input) == len(words[x]):
      for y in range(-1, len(input)-1):
        if input[y] != words[x][y] and input[y] != '_':
          valid = False
      if valid:
        words2 = words2 + (words[x])
  for x in range(0, 26):
    alphabetCount.append(0)
  for x in range(0, len(words2)):
    alphabetCount[alphabet.index(words2[x])] = alphabetCount[alphabet.index(words2[x])] + 1
  for z in range(0, 26):
    if max(alphabetCount) != 0 and (alphabet[alphabetCount.index(max(alphabetCount))]) not in input:
      guesses.append(alphabet[alphabetCount.index(max(alphabetCount))])
    alphabetCount[alphabetCount.index(max(alphabetCount))] = 0
  print (guesses)

Answer 1

出现这个问题是因为你屏蔽了内置函数 input() 作业:

input = input('Input: ')

对于一次迭代，这会工作得很好，因为您不会再次调用 input()。不过，多次执行此操作将使用被屏蔽的 input 值，在您的情况下使用 str 类型的值；调用 str 值将导致 TypeError。

将名称更改为不同的名称，例如:

my_input = input('Input: ')

为了消除错误，请确保在整个代码中进行更改。

记住切勿将用户定义的名称与 built-in function names 混合使用因为你会得到奇怪的行为。