ruby-on-rails - 从参数中剥离破折号 - Rails

Question

如何从参数中去除字符？如果我的参数是这样的:

<ActionController::Parameters {"utf8"=>"✓", "q"=><ActionController::Parameters {"search_fields_cont_any"=>"123-456", "category_eq"=>"", "created_at_gteq"=>"", "created_at_lteq"=>""} permitted: false>, "controller"=>"submissions", "action"=>"index", "page"=>nil, "per_page"=>nil} permitted: false>

params[:q][:search_fields_cont_any] => "123-456"

如何修改参数使其看起来像这样:

params[:q][:search_fields_cont_any] => "123456"

Controller

@q = Submission.submissions_for(user: current_user).ransack(filter_params(params[:q]))

私有(private)方法

def filter_params(params)
 params.require(:q).permit(:search_fields_cont_any)
end

理想情况下，我会修改私有(private)方法中的参数。我该怎么做？

Answer 1

怎么样:

def filter_params(params)
  params.require(:q).permit(:search_fields_cont_any)[:search_fields_cont_any].gsub!('-','')
end

在控制台中:

params = ActionController::Parameters.new(q: {search_fields_cont_any: 'abc-def'})
 => {"q"=>{"search_fields_cont_any"=>"abc-def"}} 
params.require(:q).permit(:search_fields_cont_any)[:search_fields_cont_any].gsub!('-','')
 => "abcdef"

或者，如 mudasobwa 所说(更好 - 为您节省 1 个字符):

def filter_params(params)
  params.require(:q).permit(:search_fields_cont_any)[:search_fields_cont_any].delete!('-')
end

同样，在控制台中:

params = ActionController::Parameters.new(q: {search_fields_cont_any: 'abc-def'})
 => {"q"=>{"search_fields_cont_any"=>"abc-def"}} 
params.require(:q).permit(:search_fields_cont_any)[:search_fields_cont_any].delete!('-')
 => "abcdef"