python - 我怎样才能让这个程序忽略标点符号

Question

我是Python新手，我不知道如何让这个程序忽略标点符号；我知道这确实效率很低，但目前我并不为此烦恼。

while True:
y="y"
n="n"

Sentence=input("Please enter your sentence: ").upper()
print("Your sentence is:",Sentence)
Correct=input("Is your sentence correct? y/n ")
if Correct==n:
    break
elif Correct==y:
    Location=0

    SplitSentence = Sentence.split(" ")
    for word in SplitSentence:
        locals()[word] = Location
        Location+=1
    print("")

    FindWord=input("What word would you like to search? ").upper()
    if FindWord not in SplitSentence:
        print("Your chosen word is not in your sentence")
    else:
        iterate=0
        WordBank=[]
        for word in SplitSentence:
            iterate=iterate+1
            if word == FindWord: 
                WordBank.append(iterate) 
        print(FindWord, WordBank) 

    break

感谢您能给我的任何帮助

Answer 1

您可以使用 Python 的 string 模块来帮助测试标点符号。

>> import string
>> print string.punctuation
!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
>> sentence = "I am a sentence, and; I haven't been punctuated well.!"

您可以在每个空格处拆分句子，以从句子中获取各个单词，然后从每个单词中删除标点符号。或者，您可以先从句子中删除标点符号，然后重新组成各个单词。我们将执行选项 2 - 列出句子中除标点符号之外的所有字符，然后将该列表连接在一起。

>> cleaned_sentence = ''.join([c for c in sentence if c not in string.punctuation])
>> print cleaned_sentence
'I am a sentence and I havent been punctuated well'

请注意，“haven't”中的撇号已被删除 - 这是完全忽略标点符号的副作用。