python - 无法返回从文件(.csv)读取的列表

Question

我一直在学习和练习python，期间我在程序中发现一处错误，但无法解决。我想返回从 csv 文件检索的列表。我尝试了下面的代码，它返回一个错误。

import csv

def returnTheRowsInTheFile(fileName):
    READ = 'r'
    listOfRows = []
    try:
        with open(fileName, READ) as myFile:
            listOfRows = csv.reader(myFile)
            return listOfRows
    except FileNotFoundError:
        print('The file ' +  fileName + ' is not found')
    except: 
        print('Something went wrong')
    finally:
        #myFile.close()
        print()

def main():
    fullString = returnTheRowsInTheFile('ABBREVATIONS.CSV') 
    for eachRow in fullString:
        print(eachRow)
    return

main()

错误是

Traceback (most recent call last): File "C:\Users\santo\workspace\PyProject\hello\FinalChallenge.py", line 36, in main() File "C:\Users\santo\workspace\PyProject\hello\FinalChallenge.py", line 32, in main for eachRow in fullString: ValueError: I/O operation on closed file.

Answer 1

解决此问题的简单方法是从函数返回一个列表。我知道您分配了 listOfRows = []，但是当您执行 listOfRows = csv.reader(myFile) 时，它被覆盖了。

所以，简单的解决方案是:

def returnTheRowsInTheFile(fileName):
    READ = 'r'
    try:
        with open(fileName, READ) as myFile:
            listOfRows = csv.reader(myFile)
        return list(listOfRows) # convert to a list
    except FileNotFoundError:
        print('The file ' +  fileName + ' is not found')
    except: 
        print('Something went wrong')

您还应该阅读pep8这是 Python 的风格指南；以了解如何命名变量和函数。