python - 检查列表中是否有元素

Question

我想检查函数中通过参数给出的字符串是否在列表中。代码本身不会产生任何错误，但它的工作方式是错误的。如果我将函数“-a”作为参数，它仍然表示它不在列表中，但它肯定在列表中。

这是代码:

def generatePassword(pLength, mode):
    password = str()
    commands = ["-a", "-n", "-s", "-allupper", "-mixupper"]
    alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p",
                "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]
    specialCharacters = ["!", "?", "&", "@",
                         "-", "=", "#", "+", "*", "/", "%", "§"]
    if mode.lower().split() not in commands:
        print("Couldn't recognize commands...")
    else:
        for n in range(pLength):
            i = random.randint(1, 2)
            if "-a" in mode.lower().split():
                password += alphabet[random.randint(0, 25)]
        print("[+]", password)

generatePassword(30, "-a")

Answer 1

你的状态不好:

if mode.lower().split() not in commands:
    print("Couldn't recognize commands...")

将其替换为(例如):

args = set(mode.lower().split())
if not set(args).issubset(set(commands)):
    print("Couldn't recognize commands...")

http://python.6.x6.nabble.com/Test-if-list-contains-another-list-td1506964.html