Python 3 枚举 : Enum inheriting another Enum doesn't work?

Question

我只是想通过引用官方 Python 文档在 Python 3 中创建一个枚举 https://docs.python.org/3.4/library/enum.html尤其是 8.13.13.2 和 8.13.13.4 示例。

我的目标是拥有一个枚举，我可以对其进行迭代、比较并拥有三个独立的属性。但我一直发现这个错误:

AttributeError: can't set attribute

__init__() 构造函数中似乎有错误。

代码:

我首先尝试了一个这样的类:

class Hand(Enum):
    FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
    FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
    FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
    THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
    DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
    PAIR = (1,'PAIR',[2,1,1,1])
    NOTHING = (0,'NOTHING',[1,1,1,1,1])

    def __init__(self, val, name, struct):
        self.val = val
        self.name = name
        self.struct = struct

    def __ge__(self, other):
        if self.__class__ is other.__class__:
            return self.value >= other.value
        return NotImplemented

    def __gt__(self, other):
        if self.__class__ is other.__class__:
            return self.value > other.value
        return NotImplemented

    def __le__(self, other):
        if self.__class__ is other.__class__:
            return self.value <= other.value
        return NotImplemented

    def __lt__(self, other):
        if self.__class__ is other.__class__:
            return self.value < other.value
        return NotImplemented

然后有两个像这样的类:

class OrderedEnum(Enum):
    def __ge__(self, other):
        if self.__class__ is other.__class__:
            return self.value >= other.value
        return NotImplemented

    def __gt__(self, other):
        if self.__class__ is other.__class__:
            return self.value > other.value
        return NotImplemented

    def __le__(self, other):
        if self.__class__ is other.__class__:
            return self.value <= other.value
        return NotImplemented

    def __lt__(self, other):
        if self.__class__ is other.__class__:
            return self.value < other.value
        return NotImplemented


class Hand(OrderedEnum):
    FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
    FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
    FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
    THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
    DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
    PAIR = (1,'PAIR',[2,1,1,1])
    NOTHING = (0,'NOTHING',[1,1,1,1,1])

    def __init__(self, val, name, struct):
        self.val = val
        self.name = name
        self.struct = struct

Answer 1

Enum 对象已经有一个 name 属性(例如，参见 8.13.13.3 )，显然你不能设置它——当你认为这是有道理的关于枚举应该如何表现。你可以像这样实现你想要的:

from enum import Enum

class OrderedEnum(Enum):
    # Same as your code.

class Hand(OrderedEnum):

    FIVE_OF_KIND  = (6, [5])
    FOUR_OF_KIND  = (5, [4,1])
    FULL_HOUSE    = (4, [3,2])
    THREE_OF_KIND = (3, [3,1,1])
    DOUBLE_PAIR   = (2, [2,2,1])
    PAIR          = (1, [2,1,1,1])
    NOTHING       = (0, [1,1,1,1,1])

    def __init__(self, val, struct):
        # No need to set self.name. It's already handled.
        self.val = val
        self.struct = struct

for h in Hand:
    print((h.name, h.val, h.struct))