python - While 循环、if-else 语句 : Guess my number game

Question

我是一个使用Python的初学者，正在编写一个“猜我的数字游戏”。到目前为止，我一切正常。计算机在 1 到 3 之间随机选择一个数字，并要求玩家猜测该数字。如果猜测值高于随机数，程序将打印“Lower”，反之亦然。玩家只有 5 次尝试机会，当尝试次数用尽时，玩家会收到一条消息，游戏就会结束。如果玩家猜对了，就会恭喜他们，游戏结束。但是，有时当数字猜对时，程序不会打印祝贺消息，我不明白为什么......

import random

print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 100.")
print("Guess carefully, you only have 5 tries!.\n")

#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 4


#guessing loop
while guess != the_number:
    if guess > the_number:
        print("Lower...")
    elif guesses <= 0:
        print("Sorry, you're out of guesses! Try again...")
        break

    elif guess < the_number:
        print("Higher...")



    guess = int(input("Take a guess: "))
    tries += 1
    guesses -= 1

    if guess == the_number:
        print("You guessed it! The number was", the_number)
        print("And it only took you", tries, "tries!\n")

Answer 1

要回答有关缺少正确号码的祝贺消息的原始问题，请以 input() 结束代码，以确保在显示最后一条消息之前它不会终止。

计算顺序:

1. 给出输入猜测
2. 减少猜测(从 5 次开始)，增加尝试(从 1 次开始)
3. 如果猜测 == 0 则立即中断
4. 评估猜测(较低、较高或等于，这将结束 while 循环)

import random

print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 3.")
print("Guess carefully, you only have 5 tries!.\n")

#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 5


#guessing loop


while guess != the_number:
    tries += 1
    guesses -= 1

    if guesses == 0:
        print("Sorry, you're out of guesses! Try again...")
        break

    elif guess > the_number:
        print("Lower...")
    elif guess < the_number:
        print("Higher...")

    

    guess = int(input("Take a guess: "))

if guess == the_number:
    print("You guessed it! The number was", the_number)
    print("And it only took you", tries, "tries!\n")

input()