python - 如何从 2 个值集的列表中提取 ID 列表

Question

所以这段代码的结果是一个像这样的列表:

[
  {'id': 'abcd', 'created_time': '2016-12-09T13:45:43+0000'},
  {'id': 'efgh', 'created_time': '2016-12-09T07:47:54+0000'},
  {'id': 'ijkl', 'created_time': '2016-12-09T07:47:34+0000'},
  {'id': 'mnop', 'created_time': '2016-12-09T07:47:09+0000'},
  {'id': 'qrst', 'created_time': '2016-12-09T07:46:52+0000'}
]]

我想得到一个像这样的列表:

ID
abcd
efgh
ijkl
mnop
qrst

我很感激任何帮助，因为我正在用这个把我的头发拉出来!

def d_values(d, depth):
    if depth == 1:
        for i in d.values():
            yield i
    else:
        for v in d.values():
            if isinstance(v, dict):
                for i in d_values(v, depth-1):
                        yield i


def Get_Message_IDs (Conversation_ID, Token):

    Request = urllib.request.urlopen('https://graph.facebook.com/v2.8/' + Conversation_ID +'?fields=messages&access_token=' + Token)
    ids = list()
    try:
        response = Request
        output = response.read()
        output = output.decode("utf-8")
        output = ast.literal_eval(output)
        output = list(d_values(output, 2))
        print(output)
    except Exception as exec:
        print(exec)

Answer 1

假设末尾额外的 ] 是一个拼写错误，您的列表看起来像一个 json 列表。因此，只需使用适当的 json 模块解析它(是的，JSON 语法和 Python 字典和列表非常相似):

import json
# response is the result of your urllib.requests.urlopen(...)
my_list = json.loads(response.read().decode('utf-8'))

# then you can access the ids 
print([element['id'] for element in my_list)

# if you want the exact output you mentioned in your question:
print("ID")
for element in my_list:
    print(element.get('id'))

顺便说一句，我建议您使用外部 requests 库而不是内置的 urllib，它将免除您解析 JSON 响应的所有痛苦:

import requests
response = requests.get('https://graph.facebook.com/v2.8/' + Conversation_ID +'?fields=messages&access_token=' + Token)
print(response.json())