c# - 使用 OpenFileDialog/C#/.Net 保留最后选择的路径

Question

我想保留最后选择的路径。这是代码:

private void testFileButton_Click(object sender, EventArgs e)
{
     fd = new OpenFileDialog();
     fd.FileName = testParameters.testFileFile;
     fd.InitialDirectory = testParameters.testFileDir;

     if (fd.ShowDialog() == DialogResult.OK)
     {                    
         try
         {
            if (fd.SafeFileName != null)
             {
                 testParameters.testFileDir = Path.GetDirectoryName(fd.FileName);
                 testParameters.testFileFile = Path.GetFileName(fd.FileName);
                 testFileLabel.Text = fd.FileName;                 
             }           
          }
          catch (IOException)
          {
              MessageBox.Show("Error: Could not read file");
          }
      }
} 

为了能够保留最后选择的路径，我尝试添加 RestorDirectory 和索引但没有得到任何结果:

private void testFileButton_Click(object sender, EventArgs e)
{
     fd = new OpenFileDialog();
     fd.FileName = testParameters.testFileFile;
     fd.InitialDirectory = testParameters.testFileDir;
     fd.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
     fd.FilterIndex = 2;
     fd.RestoreDirectory = true;

     if(...){
     ...
     }
}

然后我尝试使用“else”代替:

private void testFileButton_Click(object sender, EventArgs e)
{
    fd = new OpenFileDialog();
    fd.FileName = testParameters.testFileFile;
    fd.InitialDirectory = testParameters.testFileDir;

     if (fd.ShowDialog() == DialogResult.OK)
     {                    
         try
         {
             if (fd.SafeFileName != null)
             {
                 testParameters.testFileDir = Path.GetDirectoryName(fd.FileName);
                 testParameters.testFileFile = Path.GetFileName(fd.FileName);
                 testFileLabel.Text = fd.FileName;                 
             }  
         } 


     }
     catch (IOException)
     {
         MessageBox.Show("Error: Could not read file");
     }


    }
    else
    {
         openFileDialog1.InitialDirectory = @"C:\";
    }
} 

但还是没有任何结果..

有人知道吗？

编辑:最后一次尝试

private void testFileButton_Click(object sender, EventArgs e)
        {
             //http://stackoverflow.com/questions/7793158/obtaining-only-the-filename-when-using-openfiledialog-property-filename
             OpenFileDialog fd = new OpenFileDialog();
             fd.FileName = testParameters.testFileFile;
             Environment.CurrentDirectory = @"C:\" ;

             if (fd.ShowDialog() == DialogResult.OK )
             {                    
                 try
                 {
                    if (fd.SafeFileName != null)
                     {
                         string ffileName = fd.FileName;
                         testParameters.testFileDir = Path.GetDirectoryName(ffileName);
                         testParameters.testFileFile = Path.GetFileName(ffileName);
                         testFileLabel.Text = ffileName;

                     }

                  }
                  catch (IOException)
                  {
                      MessageBox.Show("Error: Could not read file");
                  }
              }
        }   

Answer 1

documentation状态:

true if the dialog box restores the current directory to its original value if the user changed the directory while searching for files; otherwise, false.

更新:稍微更改一下我的答案，因为我想我可能误解了您的意图:

如果我没记错的话，每次打开对话框时都会打开fd.InitialDirectory，因为根据定义这是fd 新实例的默认值>。我相信这可能是您的问题所在:每次尝试打开它时，您都在调用 fd = new OpenFileDialog();。

如果您更改代码以每次都为 fd 使用相同的实例(在外部范围中定义它，例如通过属性访问单例实例？)，它可能会记住它之前的目录本身 - 这是默认行为(您可以使用 RestoreDirectory 属性覆盖它)。

获取单例实例的例子:这将只实例化对话框一次，并在每次调用属性时返回相同的实例:

Private OpenFileDialog _fd;
private OpenFileDialog SingleFd {
    get { return _fd ?? (_fd = new OpenFileDialog()); }
}


// Now in your method, use:
var singleInstance = SingleFd;