python - 所有组合，而不是使用 if 和 elif

Question

除了对以下组合使用多个 if 和 elif 语句之外，还有其他方法吗:

这是生成我想要的所有组合的代码:

import itertools

a = ['open', 'high', 'low', 'close', 'volume']
for i in range(1,len(a)+1):
    print(list(itertools.combinations(a,i)))

[('open',), ('high',), ('low',), ('close',), ('volume',)]
[('open', 'high'), ('open', 'low'), ('open', 'close'), ('open', 'volume'), ('high', 'low'), ('high', 'close'), ('high', 'volume'), ('low', 'close'), ('low', 'volume'), ('close', 'volume')]
[('open', 'high', 'low'), ('open', 'high', 'close'), ('open', 'high', 'volume'), ('open', 'low', 'close'), ('open', 'low', 'volume'), ('open', 'close', 'volume'), ('high', 'low', 'close'), ('high', 'low', 'volume'), ('high', 'close', 'volume'), ('low', 'close', 'volume')]
[('open', 'high', 'low', 'close'), ('open', 'high', 'low', 'volume'), ('open', 'high', 'close', 'volume'), ('open', 'low', 'close', 'volume'), ('high', 'low', 'close', 'volume')]
[('open', 'high', 'low', 'close', 'volume')]

现在我的代码看起来像这样:

if self.average_open.get() and self.average_low.get() and self.average_high.get() and self.average_close.get() and self.average_volume.get():
    print("You got Open, Low, High, Close, and Volume")
elif self.average_open.get() and self.average_low.get() and self.average_high and self.average_close.get():
    print("You got Open, Low, High, and Close")
elif.........

基本上我必须对生成所有组合的代码中列出的所有组合执行此操作，并且我总共有 31 个 elif 语句......有什么方法可以做到这一点吗？

Answer 1

这是我的建议:创建所有可能的检查和相应描述符的列表；然后在列表理解中应用检查并选择成功的描述符:

actions = [(self.average_open.get, "Open"), (self.average_low.get, "Low"),\
           (self.average_high.get, "High"), (self.average_close.get, "Close"),\
           (self.average_volume.get, "Volume")]
print("You got " + ", ".join(word for fun,word in actions if fun())