c# - 返回以逗号分隔的前两个数组元素加起来等于 30 的字符串

Question

我是一名新的 C# 程序员，目前遇到以下问题:

Given an array of numbers = 
   [49, 71, 68, 26, 58, 64, 47, 16, 42, 53, 20, 15, 17, 45, 43, 52, 88, 65, 46, 82, 86, 
    69, 84, 56, 54, 28, 60, 32, 95, 29, 9, 79, 98, 51, 90, 36, 24, 62, 14, 91, 83, 3, 
    74, 30, 33, 6, 92, 40, 70, 2, 44, 31, 55, 12, 8, 89, 37, 72, 25, 81, 23, 100, 13, 
    87, 80, 18, 85, 5, 78, 10, 75, 41, 67, 94, 27, 96, 22, 73, 21, 63, 7, 34, 39, 61, 
    4, 19, 97, 93, 11, 35, 77, 76, 48, 57, 50, 99, 1, 59, 66, 38]

编写一个 C# 函数，它将返回数组中前两个数字的逗号分隔字符串，总和为 30 并立即退出。

我已经研究了一段时间，它看起来很简单，但这就是我所能想到的:

 using System;
    using System.Collections.Generic;
    using System.Linq;

    class Program
    {
       static void Main()
       {
           int[] array1 = { 49, 71, 68, 26, 58, 64, 47, 16, 42, 53, 20, 15, 17, 45, 43, 52, 88, 65, 46, 82, 86, 69, 84, 56, 54, 28, 60, 32, 95, 29, 9, 79, 98, 51, 90, 36, 24, 62, 14, 91, 83, 3, 74, 30, 33, 6, 92, 40, 70, 2, 44, 31, 55, 12, 8, 89, 37, 72, 25, 81, 23, 100, 13, 87, 80, 18, 85, 5, 78, 10, 75, 41, 67, 94, 27, 96, 22, 73, 21, 63, 7, 34, 39, 61, 4, 19, 97, 93, 11, 35, 77, 76, 48, 57, 50, 99, 1, 59, 66, 38 };
           int sum1 = array1.Sum();
           Console.WriteLine(sum1);
        }
    }

我知道我只是遗漏了一些小问题，我发现了类似的问题，但没有人为我解决这个问题。任何帮助或插入正确的方向将不胜感激。

Answer 1

功能:

static string GetFirstPairOf30(int[] data) {
    for (int i = 0; i < data.Length; i++) {
        for (int j = 0; j < data.Length; j++) {
            if (i != j && data[i] + data[j] == 30) {
                return String.Format("{0},{1}", data[i], data[j]);
            }
        }
    }
    throw new ArgumentException("Array does not contain pairs with sum 30");
}

用法:

   Console.WriteLine(GetFirstPairOf30(array1));