php - Paypal 使用 PHP cURL 获取交易详情

Question

经过大量搜索，我终于能够使用 PHP cURL 成功获取我的 Paypal 访问 token 。现在我正在尝试根据交易 ID 检索交易详细信息。到目前为止，我认为我的调用 URL 是正确的，但我认为我的发布数据格式可能不正确。使用的代码如下:

<?php

//this function is for handling post call requests
function make_post_call($url, $postdata) {
    global $token;
    $curl = curl_init($url); 
    curl_setopt($curl, CURLOPT_POST, true);
    curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true);
    curl_setopt($curl, CURLOPT_SSLVERSION , 6);
    curl_setopt($curl, CURLOPT_HEADER, false);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_HTTPHEADER, array(
                'Authorization: Bearer '.$token,
                'Accept: application/json',
                'Content-Type: application/json'
                ));

    curl_setopt($curl, CURLOPT_POSTFIELDS, $postdata); 
    $response = curl_exec( $curl );
    print_r($response); //IM NOW RECEIVING OUTPUT, however symbols are now being replaced by placeholders such as '%40', how can i prevent this?
    if (empty($response)) {
        die(curl_error($curl)); //close due to error
        curl_close($curl); 
    } else {
        $info = curl_getinfo($curl);
        echo "Time took: " . $info['total_time']*1000 . "ms\n";
        curl_close($curl); // close cURL handler
        if($info['http_code'] != 200 && $info['http_code'] != 201 ) {
            echo "Received error: " . $info['http_code']. "\n";
            echo "Raw response:".$response."\n";
            die();
        }
    }
    // Convert the result from JSON format to a PHP array 
    $jsonResponse = json_decode($response, TRUE);
    return $jsonResponse;
}

$token = get_access_token($url,$postArgs); //works and returns a valid access token

//This is the URL for the call
$url = 'https://api-3t.sandbox.paypal.com/nvp';

//This is the data to be sent in the call 
$postdata = array(
'USER' => 'peoplesroewrwwsg_api1.outlook.com', 
'PWD' => 'KR2TVKHGDSHSNDJ6E2', 
'SIGNATURE' => 'AFcWxV21C7fdFHSGGSDGD51G0BJYUWOCSyjUAKPPGs', 
'METHOD' => 'GetTransactionDetails', 
'VERSION' => '123', 
'TransactionID' => '1RE953245246192109'
);

$postdata = http_build_query($postdata); 
//$postdata = json_encode($postdata); //Is this the correct way of formatting? 

$transactionInfo = make_post_call($url, $postdata); //get transaction details NOT WORKING

print_r($transactionInfo); //does not print anything
?> 

我没有收到任何 cURL 错误，所以我认为问题要么是我发送的数据，要么是我如何格式化它。

可在此处找到有关如何执行此操作的简短 Paypal 指南-> https://developer.paypal.com/docs/classic/express-checkout/gs_transaction/#tryit但是它是用 cURL 而不是 PHP cURL 扩展编写的，所以我不确定我是否正确发送数据。

Paypal GetTransactionDetails 详情-> https://developer.paypal.com/docs/classic/api/merchant/GetTransactionDetails_API_Operation_NVP/

非常感谢有关数据格式的任何指导或任何其他建议!

-------------------------------------------- - - - - - 更新! - - - - - - - - - - - - - - - - - - - ----------------------

现在，当我在执行 cURL 语句后立即打印结果时，我会收到如下信息:

RECEIVERID=GN7SRQEGEREASDV9BQU&EMAIL=peoplesrobotiblabal%40outlook%2ecom&PAYERID=JC5RWUUKWGDFYJYY&PAYERSTATUS=verified&COUNTRYCODE=US&SHIPTONAME=Jane%20Smurf...

可以看出，一些符号(例如句点)正在被占位符(例如“%40”)替换。能否确定其来源？是因为我期待 JSON 响应吗？

Answer 1

要从 PHP 数组构建 http 查询字符串，您可以使用 PHP http_build_query()。示例:

$array = ['username' => 'John', 'password' => '123456abc'];
$postdata = http_build_query($array);

你说的符号是特殊字符的urlencoded形式。 Http 请求将要求对查询字符串进行 urlencoded。 %40 是 @ 的 urlencoded 形式。如果将来您需要对 urlencode 字符串进行编码/解码，您可以使用 rawurldecode()、rawurlencode()、urlencode()和 urldecode()。

用于解析来自 PAYPAL NVP API 的响应。您可以使用 parse_str()。示例 1:

$response = 'status=success&code=02';
parse_str($response, $response_array);
//$response_array will contain the $response as array

示例 2:

$response = 'status=success&code=02';
parse_str($response);
//this will display success
echo $status;
//this will display 02
echo $code;