python - 按下按钮后同时运行 2 个 python 脚本

Question

我想在按下按钮后同时运行 2 个 python 脚本(1.py 和 2.py)。我怎样才能做到这一点？

1.py

from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
    return 'Hello'
if __name__ == '__main__':
    app.run(debug=True, host='0.0.0.0', port = 5000)

2.py

from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
    return 'Nice to meet you'
if __name__ == '__main__':
    app.run(debug=True, host='0.0.0.0', port = 5050)

按钮.py

from Tkinter import *
root = Tk()
def Start():
    #run 1.py and 2.py

Button_Start = Button(root, text = "Start", command = Start)
Button_Start.pack(side = LEFT)
root.mainloop()

Answer 1

您可以使用线程来完成此操作，并且所有文件都应该位于同一目录中。

1. first_flask.py

from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
    return 'Hello'

def flaskThread1():
    app.run(debug=True, host='0.0.0.0', port = 5000)

2. second_flask.py

from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
    return 'Nice to meet you'

def flaskThread2():
    app.run(debug=True, host='0.0.0.0', port = 5050)

3.在按钮运行脚本中，

import thread
from first_flask import flaskThread1
from second_flask import flaskThread2

#At first button pressed
thread.start_new_thread(flaskThread1,())
thread.start_new_thread(flaskThread2,())