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python - 如何使用 rapids.ai 在 GPU 中进行矩阵点积

转载 作者:太空宇宙 更新时间:2023-11-03 15:36:31 24 4
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我正在使用 CUDF它是 Nvidia 的 Rapids ML 套件的一部分。

使用这个套件我将如何做点积?

df = cudf.DataFrame([('a', list(range(20))),
('b', list(reversed(range(20)))),
('c', list(range(20)))])

例如我如何使用相同的 cudf 对象在上述 Dataframe 上执行点积?

最佳答案

cuDF Dataframe 提供了一个apply_rows 方法,可以将方法编译到内核中并在GPU 上执行。此功能已实现 January of last year .

import cudf
import numpy

rows = 20000000

df = cudf.DataFrame([
('a_in', list(range(rows))),
('b_in', list(reversed(range(rows)))),
('c_in', list(range(rows)))
])

def kernel(a_in, b_in, c_in, dot):
for i, (a, b, c) in enumerate(zip(a_in, b_in, c_in)):
dot[i] = a * b * c

df = df.apply_rows(
kernel,
incols=['a_in', 'b_in', 'c_in'],
outcols=dict(dot=numpy.float64),
kwargs=dict()
)

[x for x in df['dot']]

农产品

[0.0,
18.0,
68.0,
144.0,
240.0,
350.0,
468.0,
588.0,
704.0,
810.0,
900.0,
968.0,
1008.0,
1014.0,
980.0,
900.0,
768.0,
578.0,
324.0,
0.0]

至于计算点积...

import cudf
import numpy
import pandas

rows = 20000000

values_a = [float(x) for x in list(range(rows))]
values_b = [float(x) for x in list(reversed(range(rows)))]
values_c = [float(x) for x in list(range(rows))]

def create_cudf_dataframe():
return cudf.DataFrame([
('a_in', values_a),
('b_in', values_b),
('c_in', values_c)
])

def create_pandas_dataframe():
return pandas.DataFrame(
data = {
'a_in': values_a,
'b_in': values_b,
'c_in': values_c
}
)


def test_cudf(df = None):

print('\ncomputing dot product using cudf')

def kernel(a_in, b_in, c_in, dot):
for i, (a, b, c) in enumerate(zip(a_in, b_in, c_in)):
dot[i] = a * b * c

if df is None:
print(' - creating dataframe using cudf')
df = create_cudf_dataframe()

df = df.apply_rows(
kernel,
incols=['a_in', 'b_in', 'c_in'],
outcols=dict(dot=numpy.float64),
kwargs=dict(),
cache_key='dot_product_3'
)

dp = df['dot'].sum()

print(dp);


def test_pandas(df = None):
print('\ncomputing dot product using pandas')
if df is None:
print(' - creating dataframe using pandas')
df = create_pandas_dataframe()

a = df['a_in']
b = df['b_in']
c = df['c_in']

dp = a.mul(b).mul(c).sum()

print(dp)

cudf_df = create_cudf_dataframe()
pandas_df = create_pandas_dataframe()

%time test_cudf()
%time test_cudf(cudf_df)
%time test_pandas()
%time test_pandas(pandas_df)

性能结果在 ubuntu@18.04 in jupyter 上运行在 i7 6700-k 上,配备 32GB 内存和 GTX 1080 ti。

computing dot product using cudf
- creating dataframe using cudf
1.333333066666688e+28
CPU times: user 1.78 s, sys: 273 ms, total: 2.06 s
Wall time: 2.05 s

computing dot product using cudf
1.333333066666689e+28
CPU times: user 19.4 ms, sys: 24 ms, total: 43.4 ms
Wall time: 43.1 ms

computing dot product using pandas
- creating dataframe using pandas
1.3333330666666836e+28
CPU times: user 7.81 s, sys: 781 ms, total: 8.59 s
Wall time: 8.57 s

computing dot product using pandas
1.3333330666666836e+28
CPU times: user 125 ms, sys: 120 ms, total: 245 ms
Wall time: 245 ms

关于python - 如何使用 rapids.ai 在 GPU 中进行矩阵点积,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54480400/

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