python - 使用 Python 进行表格格式化

Question

我正在尝试获取以下代码的输出:

for x in range(1,100):
   if x==2:
      print(x)
   else:
      for i in range (2,x):
        if x%i==0:
            break
        elif x%i!=0:
            if i==(x-1):
                print(x)

输出如下:

 2   3   5   7  11  13  17  19  23  29
31  37  41  43  47  53  59  61  67  71
73  79  83  89  97 

1. 必须只有十行
2. 个位数必须堆叠在单数上，十位数字必须堆叠在十位上，等等。

Answer 1

'%4s' %素数

如果您有素数，则可以使用 '%4s' % prime 将素数右对齐 4 个字符(您可以选择其他宽度，或根据您的范围进行调整):

primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,
          43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]

width = 4
cell_format = '%'+str(width)+'s'
cells = 10

for i,p in enumerate(primes):
    if i % 10 == 0:
        print
    print cell_format % p,

它输出:

   2    3    5    7   11   13   17   19   23   29
  31   37   41   43   47   53   59   61   67   71
  73   79   83   89   97

您的代码:

Python 2

count = 0
cells = 10
for x in range(1,100):
   if x==2:
      print('%4s' % x),
   else:
      for i in range (2,x):
        if x%i==0:
            break
        elif x%i!=0:
            if i==(x-1):
                count += 1
                if count % cells == 0:
                    print("")
                print('%4s' % x),

Python 3

count = 0
cells = 10
for x in range(1, 100):
    if x == 2:
        print('%4s' % x, end='')
    else:
        for i in range(2, x):
            if x % i == 0:
                break
            elif x % i != 0:
                if i == (x - 1):
                    count += 1
                    if count % cells == 0:
                        print("")
                    print('%4s' % x, end='')
print("")