python - 初学者 : Python Value error: invalid literal for int()

Question

我在 python 中制作了一个简单的 blackjack 程序，但是我得到了一个“ValueError:invalid literal for int() with base 10: ...”为了获得玩家手中的总值(value)，在创建卡片对象之后，我尝试获得卡的等级: rank1 = Card.Card.getRank(card1)

这是类方法:

 def getRank(self):
      if self.__rank == ('J'):
          self.__rank = 10
          return self.__rank
      elif self.__rank == ('Q'):
          self.__rank = 10
          return self.__rank
      elif self.__rank ==  ('K'):
          self.__rank = 10
          return self.__rank
      elif self.__rank == ('A'):
          self.__rank = 11
          return self.__rank
      else:
          self.__rank = self.__rank
          return int(self.__rank)`

它唯一一次返回 ValueError: invalid literal for int() with base 10 是如果等级是 'Q' 或 'K'，它为 'J' 返回 10，为 'A' 返回 11。我不明白为什么它会为 'Q' 或 'K' 返回错误，因为 'J' 和 'A' 的代码相同......任何帮助将不胜感激......如果有帮助，在此之前我有

全类同学

#Card class

#Class card holds ranks and suits of deck
#

TEN = 10
FOUR = 4

class Card():
     #Create rank list
     RANK= ["A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"]*FOUR


     #Create list with rank names
     rankNames=[None, 'Ace', 'Two', 'Three', 'Four', 'Five', 'Six', 
                'Seven', 'Eight', 'Nine', 'Ten', 'Jack', 'Queen', 'King']


     #Create suit list
     suitNames = ['CLUBS','DIAMONDS', 'HEARTS', 'SPADES']


     #Takes in rank, suit to create a deck of cards
     def __init__(self, rank, suit):
          self.__rank = rank
          self.__suit = suit


     #Returns the rank of card
     def getRank(self):
          if self.__rank == ('J'):
              print (repr(self.__rank))
              self.__rank = 10
              return self.__rank
          elif self.__rank == ('Q'):
              self.__rank = 10
              print (repr(self.__rank))
              return self.__rank
          elif self.__rank ==  ('K'):
              print (repr(self.__rank))
              self.__rank = 10
              return self.__rank
          elif self.__rank == ('A'):
              print (repr(self.__rank))
              self.__rank = 11
              return self.__rank
          else:
              self.rank = self.__rank
              print (repr(self.__rank))
              return int(self.__rank)   


     #Returns suit of card
     def getSuit(self):
          return self.__suit


     #Returns number of points the card is worth
     def BJVaue(self):
          if self.rank < 10:
               return self.rank
          else:
               return TEN


     def __str__(self):
          return "%s of %s" % ([self.__rank], [self.__suit])

这是我创建卡片对象的地方

#Create a player hand                
player = []    
#Draw two cards for player add append
player.append(drawCard())
player.append(drawCard())

#Display players cards
print ("You currently have:\n" , player)

#Get the rank of the card
card1 = player[0]
card2 = player[1]

#Update players card status
print (card1)
print (card2)

#Get the total of the hand
rank1 = Card.Card.getRank(card1)
rank2 = Card.Card.getRank(card2)

#Get the ranks of players cards
playerRank = [rank1 , rank2]

#Get total of players hand
totalPlayer = getTotal(playerRank)

#Display players total
print ("Your current total is: ", totalPlayer)

getTotal 函数

def getTotal(rank):
    #Create and set accumulator to 0
    total = 0

    #for each value in the rank
    for value in rank:
        #add to total
        total += value

    #Return total
    return total

希望对你有帮助

Answer 1

这条线不对:

  if self.__rank == ('J' or 'Q' or 'K'):

('J' or 'Q' or 'K') 的计算结果为 'J'，所以这一行只是检查 self.__rank == 'J'.

你实际上想要:

  if self.__rank in ('J', 'Q', 'K'):

我认为您的第一个代码示例应该可行。您确定您确实在运行新代码吗？如果您尝试将同一模块导入到正在运行的 Python 实例中，它不会获取更改。此外，如果您重新定义一个类，现有实例仍将具有旧方法实现。