python - 重新拆分并分隔结果

Question

如何将分隔符包含到 re.split 结果中？

比如我有文字

Bla bla lbaa dsad asd as. Asd qe as!  ASDadf asd! Dsss dwq. Dkmef? 

正则表达式

re.split('\s*([\.!\?]+)\s*', data)

并且re.split返回这个

['Bla bla lbaa dsad asd as', '.', 'Asd qe as', '!', 'ASDadf asd', '!', 'Dsss dwq', '.', 'Dkmef', '?', '']

虽然我想要这个

['Bla bla lbaa dsad asd as.', 'Asd qe as!', 'ASDadf asd!', 'Dsss dwq.']

我怎样才能做到没有尖刺？

谢谢

Answer 1

您可以尝试通过标点符号前面的空格进行拆分:

In [9]: re.split(r'(?<=[\.!\?])\s+', data)
Out[9]:
['Bla bla lbaa dsad asd as.',
 'Asd qe as!',
 ' ASDadf asd!',
 'Dsss dwq.',
 'Dkmef?']

来自 documentation for the re module 的解释:

(?<=...)

Matches if the current position in the string is preceded by a match for ... that ends at the current position. This is called a positive lookbehind assertion. (?<=abc)def will find a match in abcdef, since the lookbehind will back up 3 characters and check if the contained pattern matches. The contained pattern must only match strings of some fixed length, meaning that abc or a|b are allowed, but a* and a{3,4} are not.