gpt4 book ai didi

python - PyQtgraph y轴标签非科学计数法

转载 作者:太空宇宙 更新时间:2023-11-03 15:17:16 25 4
gpt4 key购买 nike

PyQtgraph Y 轴标签以科学计数法显示。我不希望它采用科学记数法。将标签更改为非科学的代码是什么。

enter image description here

科学计数法 - 1.70 (x1e+06)

非科学记数法1700000(我想以非科学记数法显示Y轴)。

在 main() 函数中,我调用 addXYZ 来添加等高线,然后调用 Show2dPlot 来显示等高线图。

##### add the XY contour line to plot #####       
def addXYZ(self, X, Y, Z):
self.plotwin.plot(X, Y, pen=(255,255,255))#cmap=cm.coolwarm)


##### Format 2D Plot #####
def Show2dPlot(self):
self.plotwin.setLogMode(x=False, y=False)
self.plotwin.showGrid(x=True, y=True)
self.plotwin.setLabel('left', "Easting")# units='A')
self.plotwin.setLabel('bottom', "Northing") #, units='s')
self.plotwin.setAspectLocked()
self.plotwin.set_scientific(False) #I'm getting error in set_scientific

最佳答案

PyQtgraph 不包含 set_scientific(False)。最好的解决方案是覆盖 AxisItem.tickStrings 将有助于创建自定义标签。

enter image description here

下面是代码。

import sys
from pyqtgraph.Qt import QtGui, QtCore
import pyqtgraph as pg

##### Override class #####
class NonScientific(pg.AxisItem):
def __init__(self, *args, **kwargs):
super(NonScientific, self).__init__(*args, **kwargs)

def tickStrings(self, values, scale, spacing):
return [int(value*1) for value in values] #This line return the NonScientific notation value

class MyApplication(QtGui.QApplication):
def __init__(self, *args, **kwargs):

self.win = pg.GraphicsWindow(title="Contour plotting")
self.win.resize(1000,600)

self.plot = self.win.addPlot(title='Contour', axisItems={'left': NonScientific(orientation='left')})
self.curve = self.plot.plot()


def PlotContour(self):
x = range(50000,60000,10000)#X coordinates of contour
y = range(500000,600000,100000)#Y coordinates of contour
self.curve.setData(x=x, y=y)
self.curve.autoRange()

def main():
app = MyApplication(sys.argv)
sys.exit(app.exec_())

if __name__ == '__main__':
main()

关于python - PyQtgraph y轴标签非科学计数法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43778148/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com