python - 如果语句不读取输入

Question

这个问题已经有答案了:

How to test multiple variables for equality against a single value? (31 个回答)

已关闭 6 年前。

刚刚学习如何编码，想做一个小程序来看看我所知道的。

n = int(input("Pick a number any Number: "))
if  n > 100:
    print ("No... Not that Number")
else:
    answer = input("Would you like to know your number?")
    if answer == "Y" or "Yes" or "y" or "yes":
        print ("Your number is %s" % (n))
    elif answer == "N" or "No" or "n" or "no" or "NO":
        print ("Oh, well that's a shame then.")
    else:
        print ("Please type Yes or No")

input("Press Enter/Return to Exit")

一切正常，除了第二个 if语句，该语句不遵循输入 input 中的任何数据。它这样做有什么原因吗？

Answer 1

Python 不是人类，它无法理解

 if answer == "Y" or "Yes"

按照你的意思。你应该这样做

if answer == 'Y' or answer == 'Yes'

或者更好

if answer in ('Yes', 'Y', 'yes', 'y')

或者更短

if answer.lower() in ('yes', 'y')