python - 将一个应用程序的 url 包含到 django 中另一个应用程序的 urls 文件中

Question

我的项目中有两个应用程序:学院和学生。我已将学院应用程序的 url 包含在根 url 文件中。

根 urls.py

urlpatterns += [    
    url(r'^insti/', include('institute.urls', namespace='institute')), 
]

institute/urls.py 文件

from institute import views
from django.conf.urls import url, include

app_name = "institute"
# institute urls
urlpatterns = [
    url(r'^$', views.institute_home, name='home'),
    url(r'^signin/$', views.signin, name='signin'),
    url(r'^logout/$', views.institute_logout, name='logout'),
    # other urls here
]
# students urls in institute
urlpatterns += [    
    url(r'^student/', include('students.urls', namespace='students')),
]

students/urls.py 文件

from django.conf.urls import url
from students import views

app_name = "students"
urlpatterns = [
    url(r'^$', views.students_home, name="students_home"),
    url(r'^register/$', views.register, name="register"),
    url(r'^signin/$', views.signin, name="signin"),
    url(r'^logout/$', views.students_logout, name="logout"),
    # other urls
]

当我点击 localhost/insti/sigin, localhost/insti/<anything> 这样的网址时它工作正常，但是一旦我点击 url localhost/insti/students它引发了我的错误

'students' is not a registered namespace

在我的代码中的某处 return HttpResponseRedirect(reverse("students:signin")) 行

我在学院网址中包含学生网址的方式是否错误或者存在其他问题？

Answer 1

更好的方法是:

根 urls.py

urlpatterns += [
    url(r'^insti/student/', include('students.urls', namespace='students')),
    url(r'^insti/', include('institute.urls', namespace='institute')),
]

因此您可以使用return HttpResponseRedirect(reverse("students:signin"))。

如果您不想更改网址组织，请使用此:

return HttpResponseRedirect(reverse("institue:students:signin"))