python - 尝试调用 python 函数时出现 Cronjob 错误

Question

当我尝试使用 cronjob 调用 python 函数时，它返回错误。

当我从 python shell 运行它时，该函数工作正常

这是错误:

: command not found
import: unable to open X server `' @ error/import.c/ImportImageCommand/368.
import: unable to open X server `' @ error/import.c/ImportImageCommand/368.
import: unable to open X server `' @ error/import.c/ImportImageCommand/368.
import: unable to open X server `' @ error/import.c/ImportImageCommand/368.
: command not found
: command not found
-bash: from: command not found
: command not found
: command not found
-bash: message: command not found
: command not founde is very slow,
: command not foundway either I restarted the server or it's not responding,
: command not founds down :(}
-bash: address: command not found
: command not found
: command not found
-bash: kb_log.py: line 25: syntax error near unexpected token `('
'bash: kb_log.py: line 25: `def test_speed(url="http://www.kenyabuzz.com",timeouttest=2):

文件kb_log:

import urllib2
import time
import socket
import smtplib


from django.core.mail import send_mail


message = {404:"The Page not found possibly a missing",
            "slow":"The site is very slow",
            502:"502 Gateway either I restarted the server or it's not responding",
            504:"Server is down :("}
# url = "http://www.kenyabuzz.com"
address = "hrrsnkimani103@gmail.com"
# timeoutest = 60 #seconds 


def test_speed(url="http://www.kenyabuzz.com",timeouttest=2):     
    try:
        begin_time = time.time()
        requesttest = urllib2.urlopen(url,None,timeouttest)
        requesttest.read()
        return "Site is okay with a response time of {0}".format(time.time() - begin_time)
    except socket.timeout:
        return message["slow"]   
    except urllib2.HTTPError, e:
        return message[e.code]

def send_email():
    result = test_speed()
    server = smtplib.SMTP('smtp.gmail.com', 587)
    server.starttls()
    server.login("muiruri.samuel@gmail.com", "xdjmfppkffwmiwvh")
    server.sendmail("muiruri.samuel@gmail.com", ['muiruri.samuel@gmail.com','hrrsnkimani103@gmail.com'], result)
    server.quit()

if __name__ == '__main__':    
    send_email()

我认为问题可能出在它被调用的方式上。

Answer 1

您将其作为 shell 脚本运行。 “导入”是一个程序。

将“#!/usr/bin/python2”添加到程序的顶部。操作系统将对此进行解释并启动 python 来解释您的程序。