python - 对于循环 python ？

Question

我需要帮助创建 for 循环或有关如何更好地执行此操作的建议。我有一个基于行数和列数的 0 的空列表。然后是另一个包含数据的列表。

我手动写下了如何更改值以将其可视化。

r = 2
c = 2
all_list = [[0 for x in range(c*3)] for y in range(3*r)]
a = [[[' ', 55, ' '], [57, 0, 63], [' ', 43, ' ']], [[' ', 71, ' '], [95, 1, 64], [' ', 37, ' ']], [[' ', 80, ' '], [12, 2, 49], [' ', 69, ' ']], [[' ', 63, ' '], [54, 3, 17], [' ', 84, ' ']]]

#Need to convert the list above to this.
#[[' ', 55, ' ', ' ', 71, ' '], [57, 0, 63, 95, 1, 64], [' ', 43, ' ', ' ', 37, ' '], [' ', 80, ' ', ' ', 63, ' '], [12, 2, 49, 54, 3, 17], [' ', 69, ' ', ' ', 84, ' ']]

all_list[0][0] = a[0][0][0]
all_list[0][1] = a[0][0][1]
all_list[0][2] = a[0][0][2]
all_list[0][3] = a[1][0][0]
all_list[0][4] = a[1][0][1]
all_list[0][5] = a[1][0][2]

all_list[1][0] = a[0][1][0]
all_list[1][1] = a[0][1][1]
all_list[1][2] = a[0][1][2]
all_list[1][3] = a[1][1][0]
all_list[1][4] = a[1][1][1]
all_list[1][5] = a[1][1][2]

all_list[2][0] = a[0][2][0]
all_list[2][1] = a[0][2][1]
all_list[2][2] = a[0][2][2]
all_list[2][3] = a[1][2][0]
all_list[2][4] = a[1][2][1]
all_list[2][5] = a[1][2][2]

all_list[3][0] = a[2][0][0]
all_list[3][1] = a[2][0][1]
all_list[3][2] = a[2][0][2]
all_list[3][3] = a[3][0][0]
all_list[3][4] = a[3][0][1]
all_list[3][5] = a[3][0][2]

all_list[4][0] = a[2][1][0]
all_list[4][1] = a[2][1][1]
all_list[4][2] = a[2][1][2]
all_list[4][3] = a[3][1][0]
all_list[4][4] = a[3][1][1]
all_list[4][5] = a[3][1][2]

all_list[5][0] = a[2][2][0]
all_list[5][1] = a[2][2][1]
all_list[5][2] = a[2][2][2]
all_list[5][3] = a[3][2][0]
all_list[5][4] = a[3][2][1]
all_list[5][5] = a[3][2][2]
print(all_list)

这是我目前所拥有的:

  for i in range(len(all_list)):
        for j in range(r*c):
            for k in range(r):
                for t in range(3):
                    all_list[i][j] = a[][k][t] #This is not correct

Answer 1

这个有效:

firstHalf = [thing[0]+thing[1] for thing in zip(*a)]
secondHalf = [thing[2]+thing[3] for thing in zip(*a)]
reshaped = firstHalf + secondHalf

输出

[[' ', 55, ' ', ' ', 71, ' '],
 [57, 0, 63, 95, 1, 64],
 [' ', 43, ' ', ' ', 37, ' '],
 [' ', 80, ' ', ' ', 63, ' '],
 [12, 2, 49, 54, 3, 17],
 [' ', 69, ' ', ' ', 84, ' ']]