python - 值错误: unsupported format character 'a' (0x61) at index 55 with URL string

Question

尝试使用以下代码将 URL 和主机名发送到数据库:

def sendToDatabase(self, case, filename):
103         ext = os.path.splitext(filename)[1]
104         filenoext = filename.strip(ext)
105         url = "https://apses4859.ms.ds.uhc.com:10943/rest/download/C%3A/IBM/ISA5/ISA5/isa/cases/%s/%s-analyzer_ISA_PD/%s_Leak_Suspects/index.html" % (case, filename,filenoext)
106         cursor = connection.cursor()
107         m = re.search(r"([^.]*)", filename)
108         hostname = m.group(1)
109         query = "INSERT INTO StoryData (hostName, reportName) VALUES (%s, %s)"
110         cursor.execute(query , (hostname, url))
111         connection.commit()
112         cursor.close()

出于某种原因，它不喜欢 %3A 旁边的 A。我尝试添加额外的%，但仍然没有影响。不太明白为什么我会收到此错误。

Answer 1

%3A 被解释为格式化字符串，并且没有 A 格式。最好切换到新式格式，即。使用 format 方法而不是 % 运算符:

url = "https://apses4859.ms.ds.uhc.com:10943/rest/download/C%3A/IBM/ISA5/ISA5/isa/cases/{}/{}-analyzer_ISA_PD/{}_Leak_Suspects/index.html".format(case, filename,filenoext)