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python - GMM - 对数似然不是单调的

转载 作者:太空宇宙 更新时间:2023-11-03 14:57:39 27 4
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昨天我使用期望最大化算法实现了 GMM(高斯混合模型)。

如您所知,它将一些未知分布建模为混合高斯分布,我们需要了解其均值和方差,以及每个高斯分布的权重。

这是代码背后的数学原理(没那么复杂) http://mccormickml.com/2014/08/04/gaussian-mixture-models-tutorial-and-matlab-code/

这是我的代码:

import numpy as np
from scipy.stats import multivariate_normal
import matplotlib.pyplot as plt

#reference for this code is http://mccormickml.com/2014/08/04/gaussian-mixture-models-tutorial-and-matlab-code/

def expectation(data, means, covs, priors): #E-step. returns the updated probabilities
m = data.shape[0] #gets the data, means covariances and priors of all clusters
numOfClusters = priors.shape[0]

probabilities = np.zeros((m, numOfClusters))
for i in range(0, m):
for j in range(0, numOfClusters):
sum = 0
for l in range(0, numOfClusters):
sum += normalPDF(data[i, :], means[l], covs[l]) * priors[l, 0]
probabilities[i, j] = normalPDF(data[i, :], means[j], covs[j]) * priors[j, 0] / sum

return probabilities

def maximization(data, probabilities): #M-step. this updates the means, covariances, and priors of all clusters
m, n = data.shape
numOfClusters = probabilities.shape[1]

means = np.zeros((numOfClusters, n))
covs = np.zeros((numOfClusters, n, n))
priors = np.zeros((numOfClusters, 1))

for i in range(0, numOfClusters):
priors[i, 0] = np.sum(probabilities[:, i]) / m #update priors

for j in range(0, m): #update means
means[i] += probabilities[j, i] * data[j, :]

vec = np.reshape(data[j, :] - means[i, :], (n, 1))
covs[i] += probabilities[j, i] * np.dot(vec, vec.T) #update covs

means[i] /= np.sum(probabilities[:, i])
covs[i] /= np.sum(probabilities[:, i])

return [means, covs, priors]

def normalPDF(x, mean, covariance): #this is simply multivariate normal pdf
n = len(x)

mean = np.reshape(mean, (n, ))
x = np.reshape(x, (n, ))

var = multivariate_normal(mean=mean, cov=covariance,)
return var.pdf(x)


def initClusters(numOfClusters, data): #initialize all the gaussian clusters (means, covariances, priors
m, n = data.shape

means = np.zeros((numOfClusters, n))
covs = np.zeros((numOfClusters, n, n))
priors = np.zeros((numOfClusters, 1))

initialCovariance = np.cov(data.T)

for i in range(0, numOfClusters):
means[i] = np.random.rand(n) #the initial mean for each gaussian is chosen randomly
covs[i] = initialCovariance #the initial covariance of each cluster is the covariance of the data
priors[i, 0] = 1.0 / numOfClusters #the initial priors are uniformly distributed.

return [means, covs, priors]

def logLikelihood(data, probabilities): #data is our data. probabilities[i, j] = k means probability example i belongs in cluster j is 0 < k < 1
m = data.shape[0] #num of examples

examplesByCluster = np.zeros((m, 1))
for i in range(0, m):
examplesByCluster[i, 0] = np.argmax(probabilities[i, :])
examplesByCluster = examplesByCluster.astype(int) #examplesByCluster[i] = j means that example i belongs in cluster j

result = 0
for i in range(0, m):
result += np.log(probabilities[i, examplesByCluster[i, 0]]) #example i belongs in cluster examplesByCluster[i, 0]

return result

m = 2000 #num of training examples
n = 8 #num of features for each example

data = np.random.rand(m, n)
numOfClusters = 2 #num of gaussians
numIter = 30 #num of iterations of EM
cost = np.zeros((numIter, 1))

[means, covs, priors] = initClusters(numOfClusters, data)

for i in range(0, numIter):
probabilities = expectation(data, means, covs, priors)
[means, covs, priors] = maximization(data, probabilities)

cost[i, 0] = logLikelihood(data, probabilities)

plt.plot(cost)
plt.show()

问题是对数似然表现得很奇怪。我希望它是单调增加的。但事实并非如此。

例如,对于具有 3 个高斯聚类的 8 个特征的 2000 个示例,对数似然看起来像这样(30 次迭代)-

enter image description here

所以这很糟糕。但是在我运行的其他测试中,例如一个测试有 2 个特征和 2 个集群的 15 个示例,对数似然是这样的 -

enter image description here

更好,但仍不完美。

为什么会发生这种情况,我该如何解决?

最佳答案

问题在于最大化步骤。

代码使用means计算covs。然而,这是在同一个循环中完成的,在将 means 除以概率总和之前。

这会导致估计的协方差激增。

这里有一个建议的修复:

def maximization(data, probabilities): #M-step. this updates the means, covariances, and priors of all clusters
m, n = data.shape
numOfClusters = probabilities.shape[1]

means = np.zeros((numOfClusters, n))
covs = np.zeros((numOfClusters, n, n))
priors = np.zeros((numOfClusters, 1))

for i in range(0, numOfClusters):
priors[i, 0] = np.sum(probabilities[:, i]) / m #update priors

for j in range(0, m): #update means
means[i] += probabilities[j, i] * data[j, :]

means[i] /= np.sum(probabilities[:, i])

for i in range(0, numOfClusters):
for j in range(0, m): #update means
vec = np.reshape(data[j, :] - means[i, :], (n, 1))
covs[i] += probabilities[j, i] * np.multiply(vec, vec.T) #update covs

covs[i] /= np.sum(probabilities[:, i])

return [means, covs, priors]

以及由此产生的成本函数(200 个数据点,4 个特征): Cost function

编辑:我确信这个错误是代码中的唯一问题,但是运行一些额外的示例,我有时仍然会看到非单调行为(尽管比以前更不稳定)。所以这似乎只是问题的一部分。

编辑2:协方差计算中还有另一个问题:向量乘法应该是逐元素的,而不是点积——记住结果应该是一个向量。结果现在似乎一直在单调递增。

关于python - GMM - 对数似然不是单调的,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41216856/

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