python - Django:表单处理错误。处理与另一个模型关联的表单

Question

我希望能够向教师提交评论。我有 2 个型号:

models.py

class Teacher(models.Model):
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='Teacher')

class Review(models.Model):
    teacher = models.ForeignKey(Teacher)
    #other fields

    def __str__(self):
        return self.name

forms.py

class ReviewForm(forms.ModelForm):
    class Meta:
        model = Review
        #Note no 'teacher' in fields below
        fields = ('title','star','body')

views.py 我有以下表单处理:

def teacher_view(request,**kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    #if request.method == 'POST':
    #handle the form
    review_form = ReviewForm(request.POST, instance=teacher)
    review_form.teacher=teacher
    if review_form.is_valid():
         review_form.save()
         return redirect('users:index')
    else:

出于某种原因，我似乎也得到了 else 循环。例如。该表格无效。

Urls.py

url(r'^(?P<pk>[0-9]+)/$', views.teacher_view, name='detail')

<小时/>

完整 View .py

def teacher_profile(request, **kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    reviews = Review.objects.filter(teacher_id=kwargs['pk'])
    star = Review.objects.filter(teacher_id=kwargs['pk']).aggregate(Avg('star'))
    no_of_ratings = Review.objects.filter(teacher_id=kwargs['pk']).count()

    if request.method == "POST":
        if 'booking' in request.POST:
            form = BookingForm(request.POST)
            if form.is_valid():
                #handle the form
                return redirect('users:index')
            else:
                review_form = ReviewForm()
        elif 'review' in request.POST:
            review_form = ReviewForm(request.POST)
            review_form['teacher']=teacher
            if review_form.is_valid():
                review_form.save()
                return redirect('users:index')
            else:
                form = BookingForm()
        else:
            form = BookingForm()
            review_form = ReviewForm()
    else:
        form = BookingForm()
        review_form = ReviewForm()

    return render(request, "users/teacher_detail.html", context={"form": form,
                                                                 "review_form":review_form,
                                                                 "teacher":teacher,
                                                                 "reviews":reviews,
                                                                 "star":star,
                                                                 "no_of_ratings":no_of_ratings,
                                                                 })

我再次添加了代码。我已从 view.py 中复制粘贴它，但删除了表单处理，在其中我只是定义变量并重定向到带有成功消息的另一个页面。

我认为为什么你的答案中的逻辑是错误的，因为它首先检查表格是否有效，而由于老师失踪而无效。然后我们在检查其是否有效后定义老师。我尝试通过在 form.is_valid() 之前添加 review_form['teacher']=teacher 来操作代码，但总是收到错误:

'ReviewForm' object does not support item assignment

Answer 1

如果 ReviewForm 有效，您似乎想要添加教师:

def teacher_profile(request,**kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    reviews = teacher.review_set.all()
    star = reviews.aggregate(Avg('star'))
    no_of_ratings = reviews.count()

    form = BookingForm()
    review_form = ReviewForm()

    if request.method == "POST":
        if 'booking' in request.POST:
            form = BookingForm(request.POST)
            if form.is_valid():
                #Correct handling
                return redirect('users:index')
        elif 'review' in request.POST:
            review_form = ReviewForm(request.POST)
            if review_form.is_valid():
                review = review_form.save(commit=False)
                review.teacher = teacher
                review.save()
                return redirect('users:index')
    context = {
       "form":form,
       "review_form":review_form,
       "teacher":teacher,
       "reviews":reviews,
       "star":star,
       "no_of_ratings":no_of_ratings,})
    return render(request, "users/teacher_detail.html", context)

在teacher_detail.html中添加，

{{ review_form.errors }}