python - Fom 缺少 1 个必需的位置参数 : 'request' in form

Question

我正在尝试使用以前的 stackoverflow 答案和谷歌来让我的表单工作，但似乎没有什么对我有用。

我有一个模型项目和一个项目团队，我希望用户能够从他创建的团队中进行选择并将其链接到项目。

我正在使用名为 MyUser 的自定义用户

这是我选择团队的表格:

from django import forms
from django.contrib.auth.models import User
from registration.models import MyUser
from .models import Project, Team
from django.contrib.auth import get_user_model

User = get_user_model()

class EditSelectTeam(forms.Form):

    team_choice = forms.ModelChoiceField(widget=forms.RadioSelect, queryset=None)

    def __init__(self, User, request, *args, **kwargs):
        super(EditSelectTeam, self).__init__(*args, **kwargs)
        self.fields['team_choice'].queryset = Team.objects.all().filter(team_hr_admin = request.User)

我的观点:

def TeamSelect(request):
    if request.method == "POST":
        select_form = EditSelectTeam(request.user, request.POST)
        if select_form.is_valid():
            print('sucess')
        else:
            print('Fail')

    else:
        select_form = EditSelectTeam(request)
    return render(request,'link_project.html',
                            {'select_form':select_form })

如果在我的表单中输入request.User，我会收到以下错误:

TypeError: __init__() missing 1 required positional argument: 'request'

如果我没有将用户放入我的 __init__ 中，我会收到表单，但是当我单击 POST 时，会收到错误

AttributeError: 'MyUser' object has no attribute 'user'

Answer 1

您的 __init__ 方法采用 User 和 request，

def __init__(self, User, request, *args, **kwargs):

但您只能将其中之一传递给表单:

select_form = EditSelectTeam(request.user, request.POST)
...
select_form = EditSelectTeam(request)

我将更改 __init__ 方法以仅采用 user (小写)，

def __init__(self, user, *args, **kwargs):
    super(EditSelectTeam, self).__init__(*args, **kwargs)
    self.fields['team_choice'].queryset = Team.objects.all().filter(team_hr_admin=user)

然后更改 View 以始终传递request.user。

select_form = EditSelectTeam(request.user, request.POST)
...
select_form = EditSelectTeam(request.user)