c# - 如何在知道方向、角度和距离的情况下找到位置？

Question

使用提供的图表，我知道:

• 角色在位置 A，面向 B (posA)
• 物体位于位置 B (posB)，面向随机方向。
• C (desiredAngle) 的所需角度 (20)，基于 A 到 B 的方向。
• B到C的距离

我将如何找到 C 的位置？

在下面的代码中，我设法获得了向量 BC，现在如何使用从 A 到 B 的距离定义该向量上的一个点？

//The angle of the hand in relation to the object
public float angleFromPlayer = -60f;

//Get the direction vector from the selectedObject to the actor
Vector3 objectDirectionToActor = actorParent.position - selectedObjectCenter;

//Make it horizontal (Flatten the y)
objectDirectionToActor.y = 0;

//Get the rotated vector using the desiredAngle
Vector3 rotatedVector = Quaternion.Euler(0, angleFromPlayer, 0) * objectDirectionToActor;

Answer 1

弄清楚了，这是后代的解决方案:

//How high the hand will be from the dropSurface/selectedObjectPivot
public float handOffsetFromDropSurface = 0.15f;

//The angle of the hand in relation to the object
public float targetAngleFromPlayer = -80f;

//Extra distance between selectedObjectCenter and wristBone (since the handDistance is a bit too short)
public float extraHandDistance = 0f;

Vector3 GetHandBonePositionForDropSurface(Vector3 selectedObjectCenter) {
    //Get the direction vector from the selectedObject to the actor
    Vector3 objectDirectionToActor = actorParent.position - selectedObjectCenter;

    //Make it horizontal (Flatten the y)
    objectDirectionToActor.y = 0;

    //Change vector size to 1 for multiplication
    objectDirectionToActor.Normalize();

    //Get the rotated vector using the desiredAngle
    Vector3 rotatedVector = Quaternion.Euler(0, targetAngleFromPlayer, 0) * objectDirectionToActor;

    //Get the distance we want the point to be from the center of the selectedObject
    float handDistance = 
    Vector3.Distance(playerProperties.boneRightIndexProximal.position, 
    playerProperties.boneRightHand.position) + extraHandDistance;

    //Resize vector to match the hand distance
    rotatedVector *= handDistance;

    //Get finalPosition, adding the handOffsetFromDropSurface
    Vector3 wristTargetPosition = selectedObjectCenter + rotatedVector + (Vector3.up * handOffsetFromDropSurface);

    return wristTargetPosition;
}