python googlemaps不同位置之间所有可能的距离

Question

schools=['GSGS','GSGL','JKG','JMG','MCGD','MANGD','SLSA','WHGR','WOG','GCG','LP', 
  'PGG', 'WVSG', 'ASGE','CZG', 'EAG','GI'] 

for i in range (1,17):
    gmaps = googlemaps.Client(key='')
    distances = gmaps.distance_matrix((GSGS), (schools), mode="driving"['rows'][0]['elements'][0]['distance']['text']
    print(distances)

列表的元素是学校。我不想让列表太长，所以我使用了这些缩写。我想获取“GSGS”与列表中学校之间的所有距离。我不知道第二个括号内该写什么。

distances = gmaps.distance_matrix((GSGS), (schools)

如果我这样运行它，它会输出以下错误:

Traceback (most recent call last):
File "C:/Users/helpmecoding/PycharmProjects/untitled/distance.py", line 31, in 
<module>
distances = gmaps.distance_matrix((GSGS), (schools), mode="driving")['rows'][0]['elements'][0]['distance']['text']
KeyError: 'distance'

我可以一对一地做，但这不是我想要的。如果我从学校列表中写入另一所学校并删除 for 循环，它就可以正常工作。

我知道我必须执行一个循环，以便它在列表中循环，但我不知道该怎么做。每个变量(例如“GSGS”)后面都是学校的地址/位置。为了安全起见，我删除了 key 。

Answer 1

我爸爸帮助了我，我们解决了问题。现在我有了我想要的:)现在我必须列出学校之间的所有距离。如果我明白了，我必须使用 Dijkstra 算法来找到它们之间的最短路线。感谢您的帮助!

import googlemaps

GSGS = (address)
GSGL = (address)
.    .     .
.    .     .
.    .     .

schools = 
(GSGS,GSGL,JKG,JMG,MCGD,MANGD,SLSA,WHGR,WOG,GCG,LP,PGG,WVSG,ASGE,CZG,EAG,GI)

school_names = ("GSGS","GSGL","JKG","JMG","MCGD","MANGD","SLSA","WHGR","WOG","GCG","LP","PGG","WVSG","ASGE","CZG","EAG","GI")

school_distances = ()
for g in range(0,len(schools)):
n = 0
    for i in schools:
        gmaps = googlemaps.Client(key='TOPSECRET')
        distances = gmaps.distance_matrix(schools[g], i)['rows'][0]['elements'][0]['distance']['text']
    if school_names[g] != school_names[n]:
        print(school_names[g] + " - " + school_names[n] + " " + distances)
    else:
        print(school_names[g] + " - " + school_names[n] + " " + "0 km")
    n = n + 1