python - 遍历字典并以特定格式打印

Question

我有以下字典:

# a small DB of people who stole my books

dic = {
'Cohen'     : 'Calvino' 'Evertt' 'Borges',
'Larry'     : 'The Bible', 
'Volanski'  : 'Phone Book'
}

# here's an abortive attempt to print it in a CSV format
for k in dic.keys():
    print (k, '\t')
for v in dic.keys():
    print (dic[v], ' ')

这是丑陋的输出:

Volanski    
Phone Book  
CalvinoEverttBorges  
The Bible  
Cohen   
Phone Book  
CalvinoEverttBorges  
The Bible  
Larry   
Phone Book  
CalvinoEverttBorges  
The Bible 

这就是我希望输出的样子:

Cohen      Larry       Volanski  
Calvino    The Bible   Phone Book  
Evertt  
Borgest  

(只有制表符分隔，我没有在这里显示)

Answer 1

你可以设计出更整洁的格式

dic = {'Cohen'     : ['Calvino', 'Evertt', 'Borges'],
       'Larry'     : ['The Bible'],
       'Volanski'  : ['Phone Book']}

# Get max name size
mx_nm_len = len(max(dic,key=len))
mx_bk_len = max([len(max(books, key=len)) for books in dic.itervalues()])

# Store max name size + 1
mx = max([mx_nm_len, mx_bk_len]) + 1

# Store people
keys = dic.keys()

# Create generic format code to print neat list
fmat = ("%-"+str(mx)+"s")*len(keys)

# Print header line
print fmat % tuple(keys)

# similar to zip command but works for any number of lists
# Assumes all dic.values() are lists
# "zips" to longest list and uses None when any given list runs out of values
books = map(None, *dic.values())

# replaces None values in row outputs with empty strings and prints result using
# string format code (fmat)
for row in books:
    row = tuple([book if book!= None else "" for book in row])
    print fmat % row