python - 如何包含包含另一个模板的模板？

Question

我有 index.html，它加载 project/p1.html，它加载 project/p2.html。 project/p1.html 和 project/p2.html 各自加载正常，所以我知道它们工作正常。问题是试图将 project/p1.html 加载到 index.html 中，其中包含以下语句:

{% include 'project/p1.html' %}

project/p1.html 有声明:

{% include 'project/p2.html' %}

加载 index.html，出现错误:

VariableDoesNotExist at /
Failed lookup for key [objects] in u"[{'params': {}}, {'csrf_token': <django.utils.functional.__proxy__ object at 0x7fd3dc0e2410>}, {'perms': <django.contrib.auth.context_processors.PermWrapper object at 0x7fd3dc0e2210>, 'user': <django.utils.functional.SimpleLazyObject object at 0x7fd3dc10c790>}, {},......

如果我从 project/p1.html 中删除“{% include 'project/p2.html' %}”，index.html 加载正常并且错误消息消失(但显然我看不到我的内容)。

我该如何解决？

编辑:继承人“project/p2.html”:

<table class="mytable">

{% for object in objects %}
    <tr class="my_row">
      <td>{{ object.name }}</td>
    </tr>
{% endfor %}
</table>

这里是views.py:

from models import Mytable
from django.shortcuts import render_to_response, RequestContext

def my_request(request,
    template="project/p1.html",
    page_template="project/p2.html"):
    context = {
        'objects': Mytable.objects.all().order_by('-date'),
        'page_template': page_template,
    }

    if request.is_ajax():
        template = page_template
    return render_to_response(template, context,
        context_instance=RequestContext(request))

Answer 1

它正在寻找对其不可用的变量。传入额外的上下文参数。

{% include "name_snippet.html"with person="Jane"greeting="Hello"%}

编辑:Documentation .