c# - WPF datagridtextcolumn - 始终显示文本框

Question

默认情况下，WPF 数据网格文本显示为标签，并在单击时进入编辑状态。有没有办法修改列，使文本框始终可见(而不是依赖于点击事件)？提前致谢，日语

Answer 1

我根据您在评论中的澄清更新了我的答案。您可以自己为单元格设置模板。下面是年龄列使用文本 block 的示例。

XAML:

<Window x:Class="GridTest.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:Controls="clr-namespace:Microsoft.Windows.Controls;assembly=WPFToolkit"
    Height="300" Width="300">
    <StackPanel>
        <Controls:DataGrid Name="dataGrid" AutoGenerateColumns="False" >
            <Controls:DataGrid.Columns>
                <Controls:DataGridTextColumn 
                    Header="Name" 
                    Binding="{Binding Path=Name}" />
                <Controls:DataGridTemplateColumn Header="Age">
                    <Controls:DataGridTemplateColumn.CellTemplate>
                        <DataTemplate>
                            <TextBox Text="{Binding Path=Age}" />
                        </DataTemplate>
                    </Controls:DataGridTemplateColumn.CellTemplate>
                    <Controls:DataGridTemplateColumn.CellEditingTemplate>
                        <DataTemplate>
                            <TextBox Text="{Binding Path=Age}" />
                        </DataTemplate>
                    </Controls:DataGridTemplateColumn.CellEditingTemplate>
                </Controls:DataGridTemplateColumn>
            </Controls:DataGrid.Columns>
        </Controls:DataGrid>
    </StackPanel>
</Window>

代码隐藏:

using System;
using System.Collections.Generic;
using System.Windows;

namespace GridTest
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();

            dataGrid.ItemsSource = new List<Person>(
                new Person[]
                {
                    new Person("Bob", 30),
                    new Person("Sally", 24),
                    new Person("Joe", 17)
                });
        }
    }

    public class Person
    {
        public String Name { get; set; }
        public int Age { get; set; }

        public Person(String name, int age)
        {
            Name = name;
            Age = age;
        }
    }
}