python - 如何计算 KEYDOWN 的耗时。 (Python)

Question

我想知道如果按住某个键较长时间如何增加变量。我正在使用 Python 和 PyGame。这是我的代码示例(速度、圈数和距离在前面的行中定义):

distance_control = 1
for i in range(amount):
    x[i] += speedx[i]
    if x[i] >= 800:
        x[i] -= 800
        lap[i] += 1
    if event.type == pygame.KEYDOWN:
        if event.key == pygame.K_SPACE:
            x[2] += 1
    distance[i] = (lap[i] - 1)*800 + x[i]

我想知道如何做到这一点，以便您按住空格键的时间越长，speed_control 就越高，并且最大 speed_control 为 5，最好使用某种耗时的东西。

Answer 1

您可以使用pygame.time.get_ticks()函数返回自程序开始计算耗时以来的时间。当用户按下按键时，将 start_time 设置为事件循环中的当前时间，在 while 循环中，您可以使用 pygame.key.get_pressed() 检查它是否仍被按住。并计算耗时。

import pygame as pg


def main():
    screen = pg.display.set_mode((320, 240))
    clock = pg.time.Clock()
    start_time = 0

    done = False
    while not done:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                done = True
            elif event.type == pg.KEYDOWN:
                if event.key == pg.K_SPACE:
                    start_time = pg.time.get_ticks()

        keys = pg.key.get_pressed()
        if keys[pg.K_SPACE]:  # The spacebar is held.
            current_time = pg.time.get_ticks()
            elapsed_time = current_time-start_time  # milliseconds
            print(elapsed_time)

        screen.fill((30, 30, 30))
        pg.display.flip()
        clock.tick(30)


if __name__ == '__main__':
    pg.init()
    main()
    pg.quit()

<小时/>

如果您只想计算帧数:

import pygame as pg


def main():
    screen = pg.display.set_mode((320, 240))
    clock = pg.time.Clock()
    counter = 0

    done = False
    while not done:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                done = True
            elif event.type == pg.KEYDOWN:
                if event.key == pg.K_SPACE:
                    counter = 0 # Set it back to 0.

        keys = pg.key.get_pressed()
        if keys[pg.K_SPACE]:  # The spacebar is held.
            # Increment the counter every frame.
            counter += 1
            print(counter)

        screen.fill((30, 30, 30))
        pg.display.flip()
        clock.tick(30)


if __name__ == '__main__':
    pg.init()
    main()
    pg.quit()