python - Django 获取 "first_name"是此函数的无效关键字参数“创建模型类的实例时出现类型错误

Question

使用 Django 1.11 和 django-pyodbc-azure 最新版本(如果相关)。

我是 Django 新手，一直遵循 1.11 教程，在此之前没有任何问题，但我感到非常困惑。

这是我的 models.py:

from django.db import models

# Create your models here.


class Player(models.Model):
    first_name = models.CharField(max_length=20, name='First Name')
    last_name = models.CharField(max_length=20, name='Last Name')

    def __str__(self):
        return '{}, {} ({})'.format(self.last_name, self.first_name, self.id)


class Game(models.Model):
    players = models.ManyToManyField(Player, name='Players')

    def __str__(self):
        return ' vs. '.join(self.players)


class Round(models.Model):
    GIN = 'GI'
    UNDERCUT = 'UN'
    KNOCK = 'KN'
    ENDING_ACITONS = (
        (GIN, 'Gin'),
        (UNDERCUT, 'Undercut'),
        (KNOCK, 'Knock'),
    )

    game = models.ForeignKey(Game, on_delete=models.CASCADE, name='Parent Game')
    winner = models.ForeignKey(Player, on_delete=models.CASCADE, name='Winning Player')
    points = models.IntegerField(name='Points Awarded')
    end = models.CharField(max_length=2, choices=ENDING_ACITONS)

    def __str__(self):
        return '{} awarded {} points via {}'.format(self.winner, self.points, self.end.name)

现在当我运行manage.py shell并输入:

from game.models import *
bobby = Player(first_name='Bobby', last_name='Fisher')

我遇到了这个错误:

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "C:\Users\mteper\PycharmProjects\GinRummy\venv\lib\site-packages\django\db\models\base.py", line 571, in __init__
    raise TypeError("'%s' is an invalid keyword argument for this function" % list(kwargs)[0])
TypeError: 'first_name' is an invalid keyword argument for this function

任何见解都将不胜感激，因为正如我之前所说，我对 Django 和 Python 总体来说是新手。

Answer 1

name 参数导致了问题。您应该设置 verbose_name相反。

class Player(models.Model):
    first_name = models.CharField(max_length=20, verbose_name='First Name')
    last_name = models.CharField(max_length=20, verbose_name='Last Name')