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Python密码程序

转载 作者：太空宇宙 更新时间：2023-11-03 14:12:24 24 4
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<分区>

我是一名初级程序员，我认为创建一个循环遍历“所有”可能密码的程序会很酷。在 1-10 的范围内，您对以下“黑客程序”的效率评价如何？有没有办法让下面的代码更高效？您可能知道的任何算法或技巧？

我考虑过将“e”和更常见的字母移动到我的字符数组的开头，因为这些字母使用得更频繁。

import sys

password = raw_input("Enter a password: ")

characters = []
lower = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
upper = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
number = ["1","2","3","4","5","6","7","8","9","0"]
symbol = ["!","@","#","$","%","^","&","*","(",")","_","+","-","="]

#Creates array with most keyboard characters
for i in range(len(lower)):
    characters.append(lower[i])
for i in range(len(upper)):
    characters.append(upper[i])
for i in range(len(number)):
    characters.append(number[i])
for i in range(len(symbol)):
    characters.append(symbol[i])

found = False

#For 1 character passwords
for a in range(len(characters)):
    if (characters[a] == password):
        print (characters[a])
        found = True
if (found):
    sys.exit()

#For 2 character passwords
for a in range(len(characters)):
    for b in range(len(characters)):
        if (characters[a] + characters[b] == password):
            print (characters[a] + characters[b])
            found = True
if (found):
    sys.exit()

for a in range(len(characters)):
    for b in range(len(characters)):
        for c in range(len(characters)):
            if (characters[a] + characters[b] + characters[c] == password):
                print (characters[a] + characters[b] + characters[c])
                found = True
if (found):
    sys.exit()

for a in range(len(characters)):
    for b in range(len(characters)):
        for c in range(len(characters)):
            for d in range(len(characters)):
                if (characters[a] + characters[b] + characters[c] + characters[d] == password):
                    print (characters[a] + characters[b] + characters[c] + characters[d])
                    found = True
if (found):
    sys.exit()

for a in range(len(characters)):
    for b in range(len(characters)):
        for c in range(len(characters)):
            for d in range(len(characters)):
                for e in range(len(characters)):
                    if (characters[a] + characters[b] + characters[c] + characters[d] + characters[e] == password):
                        print (characters[a] + characters[b] + characters[c] + characters[d] + characters[e])
                        found = True
if (found):
    sys.exit()

24 4 0
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