python - 如何使用python3提取样本前面的文字？

Question

这是我拥有的示例记录。

Record ID:           9211
User name:           Administrator first
User principal name: Administrator@example.com
When created:         1999-12-23 3:8:52
When changed:         2000-06-10 4:8:55
Account expires:      Never

我想从值前面提取数据。输出必须如下所示:

9211
Administrator first
Administrator
first
Administrator@example.com
1999-12-23 3:8:52
2000-06-10 4:8:55
Never

单词Administrator first必须如上所示提取和分隔。
我尝试了以下操作以从样本中提取 User name 但没有得到任何输出。

re.findall(r'User name:           (\w+)', i)

请告诉我如何实现这一目标？应该只有提取的数据，而不是在数据之前给出的空间。

请告诉我如何实现这一目标？

Answer 1

你可以使用字典理解

import re

string = """
Record ID:           9211
User name:           Administrator first
User principal name: Administrator@example.com
When created:         1999-12-23 3:8:52
When changed:         2000-06-10 4:8:55
Account expires:      Never
"""

rx = re.compile(r'^(?P<key>[^:\n]+):\s*(?P<value>.+)', re.MULTILINE)
result = {m.group('key'): m.group('value') for m in rx.finditer(string)}
print(result)

之后，只需向您的字典询问 ie result['User name']。参见 a demo on ideone.com .

---

如果您有 多次出现的条目，并且条目始终具有相同的格式(即它们以 Record ID 开头并以 结尾Account expires)，你可以用另一个表达式和一个类来包裹它，这样你就可以得到一个 字典列表:

import re
string = """
Record ID:           9211
User name:           Administrator first
User principal name: Administrator@example.com
When created:         1999-12-23 3:8:52
When changed:         2000-06-10 4:8:55
Account expires:      Never

Record ID:           9390
User name:           Administrator first
User principal name: Administrator@example.com
When created:         1999-12-23 3:8:52
When changed:         2000-06-10 4:8:55
Account expires:      Never
"""

class Analyzer:
    ''' Parses the input string and returns matched entries '''
    rx_parts = re.compile(r'^Record ID:(?s:.+?)^Account expires:.+', re.MULTILINE)
    rx_entries = re.compile(r'^(?P<key>[^:\n]+):\s*(?P<value>.+)', re.MULTILINE)
    result = list()

    def __init__(self, input_string = None):
        self.result = [{m.group('key'): m.group('value') 
                        for m in self.rx_entries.finditer(part.group(0))}
                        for part in self.rx_parts.finditer(input_string)]

    def query(self, key=None, value=None):
        try:
            subset = [item for item in self.result if item[key] == value]
        except KeyError:
            subset = []
        return subset

a = Analyzer(string)
admin = a.query(key = 'Record ID', value='9390')
print(admin)