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python - 如何将值列表迭代为字符串?

转载 作者:太空宇宙 更新时间:2023-11-03 14:05:29 24 4
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我是Python新手,所以请原谅我缺乏理解。

我可以使用 BeatifulSoup4 下载 aapl 的数据,将数据分配给特定变量并使用变量创建字典。不过,我想做的是通过网站链接迭代 stock 列表,并为列表中的不同公司多次运行相同的代码,最终为每个公司提供一个字典。

import bs4 as bs
import urllib.request


stocks = ['aapl', 'nvda', 'amgn']

sauce = urllib.request.urlopen('https://www.zacks.com/stock/quote/aapl/balance-sheet')
soup = bs.BeautifulSoup(sauce,'lxml')

#Cash & Cash Equivalents
cash_and_equivalents2017 = soup.find_all('td')[33].string
cash_and_equivalents2017 = int(cash_and_equivalents2017.replace(',',''))
cash_and_equivalents2016 = soup.find_all('td')[34].string
cash_and_equivalents2016 = int(cash_and_equivalents2016.replace(',',''))

#Receivables
receivables2017 = soup.find_all('td')[40].string
receivables2017 = int(receivables2017.replace(',',''))
receivables2016 = soup.find_all('td')[41].string
receivables2016 = int(receivables2016.replace(',',''))


aapl = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}
}
print(aapl)

它为 aapl 输出以下内容:

{'Cash & Cash Equivalents': {'2017': 74181, '2016': 67155}, 'Receivables': {'2017': 29299, '2016': 30343}}

上面是原始代码,我想用 sauce 中的 aapl 替换 stocks 中的其他字符串值,最终得到多个如下所示的字典,这样我只需将不同公司的数据输入到 stock 列表中,就可以将它们自动下载到 3 个不同的字典中。

sauce = urllib.request.urlopen('https://www.zacks.com/stock/quote/[stocks]/balance-sheet')

[stocks] = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}

输出应该是 3 个字典,名称分别为 aaplnvdaamgn

aapl = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}

nvda = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}

amgn = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}

感谢您的时间和帮助,非常感谢。

最佳答案

我不确定我是否正确理解了您的问题。

您想对 stocks = ['aapl', 'nvda', 'amgn'] 中的每个条目发出一个请求并进行处理吗?

如果是这样,在 Python 中,您可以使用 for 循环迭代列表或字典,如下所示:

for stock in stocks:
# Do your processing here

针对您的情况,您可以执行以下操作:

使用字典而不是列表并将处理后的数据存储在其中。

stocks = {'aapl': {}, 'nvda': {}, 'amgn': {}}
for stock in stocks:

sauce = urllib.request.urlopen(
f'https://www.zacks.com/stock/quote/{stock}/balance-sheet')
soup = bs.BeautifulSoup(sauce, 'lxml')

# Cash & Cash Equivalents
cash_and_equivalents2017 = soup.find_all('td')[33].string
cash_and_equivalents2017 = int(cash_and_equivalents2017.replace(',', ''))
cash_and_equivalents2016 = soup.find_all('td')[34].string
cash_and_equivalents2016 = int(cash_and_equivalents2016.replace(',', ''))

# Receivables
receivables2017 = soup.find_all('td')[40].string
receivables2017 = int(receivables2017.replace(',', ''))
receivables2016 = soup.find_all('td')[41].string
receivables2016 = int(receivables2016.replace(',', ''))

stocks[stock] = {'Cash & Cash Equivalents':
{'2017': cash_and_equivalents2017,
'2016': cash_and_equivalents2016},
'Receivables':
{'2017': receivables2017,
'2016': receivables2016}
}

print(stocks)

对于url字符串,我使用了litteral string interpolation method

将输出以下内容:

{
'aapl':
{
'Cash & Cash Equivalents':
{
'2017': 'some value',
'2016': 'some value'
},
'Receivables':
{
'2017': 'some value',
'2016': 'some value'
}
},
'nvda':
{
'Cash & Cash Equivalents':
{
'2017': 'some value',
'2016': 'some value'
},
'Receivables':
{
'2017': 'some value',
'2016': 'some value'
}
},
'amgn':
{
'Cash & Cash Equivalents':
{
'2017': 'some value',
'2016': 'some value'
},
'Receivables':
{
'2017': 'some value',
'2016': 'some value'
}
}
}

祝你有美好的一天。

关于python - 如何将值列表迭代为字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48927318/

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