python - 如何在 Python 中对文件路径进行切片

Question

我对Python和编程都很陌生，我想对文件夹路径进行切片。比如我原来的路径是:

C:/Users/arul/Desktop/jobs/project_folder/shots/shot_folder/elements/MexicoCity-Part1/

我想得到这样的路径:

C:/Users/arul/Desktop/jobs/project_folder/shots/shot_folder/

在Python中有哪些实现方法？

Answer 1

您可以使用 pathlib模块:

from pathlib import Path

pth = Path('C:/Users/arul/Desktop/jobs/project_folder/shots/shot_folder/')

print(pth)
print(pth.parent)
print(pth.parent.parent)  # C:/Users/arul/Desktop/jobs/project_folder

该模块有很多非常方便的方法来处理路径:你的问题也可以使用 parts 来解决。像这样:

print('/'.join(pth.parts[:-2]))

在 Python 2.7 中，您可以使用 os.path 构建自己的 parts 函数:

from os import path

pth = 'C:/Users/arul/Desktop/jobs/project_folder/shots/shot_folder/'

def parts(pth):
    ret = []
    head, tail = path.split(pth)
    if tail != '':
        ret.append(tail)
    while head != '':
        head, tail = path.split(head)
        ret.append(tail)
    return ret[::-1]

ret = path.join(*parts(pth)[:-2])
print(ret)  # C:/Users/arul/Desktop/jobs/project_folder