python - 如何检查数据框中是否存在值

Question

您好，我正在尝试获取包含特定单词的数据框的列名，

例如:我有一个数据框，

NA              good    employee
Not available   best    employer
not required    well    manager
not eligible    super   reportee

my_word=["well"]

如何判断df中是否存在“well”以及含有“well”的列名

提前致谢!

Answer 1

使用DataFrame.isin用于检查所有列和 DataFrame.any每行检查至少一个 True:

m = df.isin(my_word).any()
print (m)
0    False
1     True
2    False
dtype: bool

然后过滤得到列名:

cols = m.index[m].tolist()
print(cols)
[1]

数据:

print (df)
               0      1         2
0            NaN   good  employee
1  Not available   best  employer
2   not required   well   manager
3   not eligible  super  reportee

详细信息:

print (df.isin(my_word))
       0      1      2
0  False  False  False
1  False  False  False
2  False   True  False
3  False  False  False

print (df.isin(my_word).any())
0    False
1     True
2    False
dtype: bool

编辑转换后得到嵌套的list，所以flattening是必要的:

my_word=["well","manager"]

m = df.isin(my_word).any()
print (m)
0    False
1     True
2     True
dtype: bool

nested = df.loc[:,m].values.tolist()
flat_list = [item for sublist in nested for item in sublist]
print (flat_list)
['good', 'employee', 'best', 'employer', 'well', 'manager', 'super', 'reportee']