python - 在 python 中组合列表中的第一个元素和同一列表的其他元素

Question

我对 python 有一个要求，将与列表中第一个元素的组合视为常见组合，并采用其他组合。

list1=['EXCHANGE_US_M','1021,2360','1256,14536,5429','AED589L','DOL895']

我有一个上面的列表，我想要如下的组合。

'EXCHANGE_US_M/0','1021','1256','AED589L','DOL895',
'EXCHANGE_US_M/1','1021','14536','AED589L','DOL895',
'EXCHANGE_US_M/2','1021','15429','AED589L','DOL895',
'EXCHANGE_US_M/3','2360','1256','AED589L','DOL895',
'EXCHANGE_US_M/4','2360','14536','AED589L','DOL895',
'EXCHANGE_US_M/5','2360','5429','AED589L','DOL895',

Answer 1

>>> from itertools import product
... 
... list1 = ['EXCHANGE_US_M', '1021,2360', '1256,14536,5429', 'AED589L', 'DOL895']
... 
... for i, p in enumerate(product(*[elem.split(',') for elem in list1])):
...     print(('{}/{}'.format(p[0], i), *p[1:]))
... 
('EXCHANGE_US_M/0', '1021', '1256', 'AED589L', 'DOL895')
('EXCHANGE_US_M/1', '1021', '14536', 'AED589L', 'DOL895')
('EXCHANGE_US_M/2', '1021', '5429', 'AED589L', 'DOL895')
('EXCHANGE_US_M/3', '2360', '1256', 'AED589L', 'DOL895')
('EXCHANGE_US_M/4', '2360', '14536', 'AED589L', 'DOL895')
('EXCHANGE_US_M/5', '2360', '5429', 'AED589L', 'DOL895')