Python随机猜谜游戏

Question

实现 GuessNumber 游戏。在这个游戏中，电脑 - 想一个 0-50 范围内的随机数。 (提示:使用随机模块。) - 反复提示用户猜测神秘号码。 - 如果猜对了，恭喜用户中奖。如果猜测不正确，让用户知道猜测是太高还是太低。 - 猜错 5 次后，告诉用户正确答案。

下面是正确输入输出的例子。

I’m thinking of a number in the range 0-50. You have five tries to
guess it.
Guess 1? 32
32 is too high
Guess 2? 18
18 is too low
Guess 3? 24
You are right! I was thinking of 24!

这是我到目前为止得到的:

import random

randomNumber = random.randrange(0,50)
print("I’m thinking of a number in the range 0-50. You have five tries to guess it.")
guessed = False

while guessed == False:
    userInput = int(input("Guess 1?"))
    if userInput == randomNumber:
        guessed = True
        print("You are right! I was thinking of" + randomNumber + "!")
    elif userInput>randomNumber:
        print(randomNumber + "is too high.")
    elif userInput < randomNumber:
        print(randomNumber + "is too low.")
    elif userInput > 5:
        print("Your guess is incorrect. The right answer is" + randomNumber)

print("End of program")

我一直遇到语法错误，我不知道如何在用户输入错误答案时让猜测值增加一，例如，猜 1？、猜 2？、猜 3？、猜 4？，猜 5？等...

Answer 1

既然您知道循环执行了多少次，并且想对它们进行计数，请使用 for 循环来控制该部分。

for guess_num in range(1, 6):
    userInput = int(input(f"Guess {guess_num} ? "))
    if userInput == randomNumber:
        # insert "winner" logic here
        break
    # insert "still didn't guess it" logic here

你知道它是如何工作的吗？