python - 无法使用selenium触发对某个链接的点击

Question

我用 python 用 selenium 编写了一个脚本，用于单击网页中的某个链接来下载 Excel 文件。但是，当我执行脚本时，它会抛出超时异常。我怎样才能让它发挥作用？任何帮助将不胜感激。

网站链接:webpage

我尝试过的脚本:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Chrome()
wait = WebDriverWait(driver, 10)
driver.get('replace_with_above_link')

item = wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, ".hasmore #dlink")))
item.click()
driver.quit()

包含下拉选项的 Html 元素:

<li class="hasmore drophover"><span>Share &amp; more</span><div><ul><li><button class="tooltip" tip="Use a customizable report creator that can<br>output HTML, CSV, or a shareable link." id="share_on_ajax_result_table">Modify &amp; Share Table</button></li><li><button class="tooltip" tip="Get a bit of widget code to emed this table on your site">Embed this Table</button></li><li><button class="tooltip" tip="Convert the table below to comma-separated values<br>suitable for use with excel">Get as Excel Workbook (experimental)</button><a id="dlink" style="display: none;"></a></li><li><button class="tooltip" tip="Export table as <br>suitable for use with excel">Get table as CSV (for Excel)</button></li><li><button class="tooltip" tip="">Strip Mobile Formatting</button></li><li><a id="a_ajax_result_table" name="ajax_result_table" href="#ajax_result_table::none">Copy Link to Table to Clipboard</a></li><li><button class="tooltip" tip="">About Sharing Tools</button></li><li><button class="tooltip" tip=""><a href="https://www.youtube.com/watch?v=MWapXbaWs_U&amp;feature=youtu.be" target="_blank">Video: SR Sharing Tools &amp; How-to</a></button></li><li><button class="tooltip" tip=""><a href="https://www.youtube.com/watch?v=JkDLV0roT14&amp;feature=youtu.be" target="_blank">Video: Stats Table Tips &amp; Tricks</a></button></li></ul></div></li>

该文件在该网页中的位置(所需的链接用铅笔标记):

Answer 1

目标链接是隐藏的，因此等待其可见性总是会失败。您应该尝试处理 button 节点:

item = wait.until(EC.visibility_of_element_located((By.XPATH, "//li[span='Share & more']")))
item.click()
wait.until(lambda driver: "drophover" in item.get_attribute("class"))
item.find_element_by_xpath("//button[.='Get as Excel Workbook (experimental)']").click()