python - 将字符串合并在一起，直到出现一个符号

Question

将字符串合并到列表中，直到字符串中出现一个符号。

names = ['My name is john.', 'My', 'name', 'is Andrew.']

“我叫约翰。”是正确的

如何连接:"My name is Andrew."？知道列表可能不同。

symbols = ['.', ':']
for i in range(len(names)-1):
   if names[i][-1] not in symbols:
      print(names[i] + ' ' + names[i+1]) 

试过这个是有效的，但不是我想要的。

有没有人有什么想法或建议？

Answer 1

您可以利用print() 的end 可选参数。

names = ['My name is john.', 'My', 'name', 'is Andrew.']
symbols = ['.', ':']
for phrase in names:
    print(phrase, end=" ")
    if (phrase[-1] in symbols):
        print()

输出:

My name is john. 
My name is Andrew. 

如果你想将它们存储在一个列表中，你可以轻松地使用两个不同的列表:

names = ['My name is john.', 'My', 'name', 'is Andrew.']
symbols = ['.', ':']
phrases = []
current = []
for phrase in names:
    current.append(phrase)
    if (phrase[-1] in symbols):
        phrases.append(" ".join(current))
        current = []
print(phrases)

输出:

['My name is john.', 'My name is Andrew.']

我们可以使用单个列表:

names = ['My name is john.', 'My', 'name', 'is Andrew.']
symbols = ['.', ':']
phrases = [""]
for phrase in names:
    phrases[-1] += phrase
    if (phrase[-1] in symbols):
        phrases.append("")
del phrases[-1] # Remove the last empty append
print(phrases)

输出:

['My name is john.', 'Mynameis Andrew.']

或者如果你喜欢Regular Expresions :

import re
names = ['My name is john.', 'My', 'name', 'is Andrew.']
print([phrase.strip() for phrase in re.split(r"[\.:]", " ".join(names))[:-1]])

输出:

['My name is john', 'My name is Andrew']

接受一些边缘情况:

results = [phrase.strip() for phrase in re.split(r"[\.:]", " ".join(names))[:-1]]
if (results[-1] == ""):
    del results[-1]
print(results)

使用:

>>> ['My name is john.', 'My', 'name', 'is Andrew.', 'test test']
['My name is john', 'My name is Andrew', 'test test']

要保留 . 和 :，您应该使用 @Jon clements评论:

import re
names = ['My name is john.', 'My', 'name', 'is Andrew.']
print([phrase.strip() for phrase in re.findall('(.*?[:.])', ' '.join(names))])

输出:

['My name is john.', 'My name is Andrew.']

接受一些边缘情况:

results = [phrase.strip() for phrase in re.findall('(.*?[:.])', ' '.join(names)) if phrase]
if (results[-1] in [".", ":"]):
    del results[-1]
else:
    results[-1] = results[-1][:-1]
print(results)

使用:

>>> ['My name is john.', 'My', 'name', 'is Andrew.', 'test test']
['My name is john.', 'My name is Andrew.', 'test test']