python - 获取函数的局部变量

Question

我正在尝试从装饰器中获取局部变量。一个例子:

def needs_privilege(privilege, project=None):
    """Check whether the logged-in user is authorised based on the
    given privilege

    @type privilege: Privilege object, id, or str
    @param privilege: The requested privilege"""

    def validate(func, self, *args, **kwargs):
        """Validator of needs_privillige"""
        try: check(self.user, privilege, project)
        except AccessDenied:
            return abort(status_code=401)
        else: 
            return func(self, *args, **kwargs)

    return decorator(validate)

装饰函数后，像这样:

 @needs_privilege("some_privilege")
 def some_function():
     pass

我想从 some_function 中检索“特权”变量(validate() 使用)。搜索了一个多小时后，我感到很迷茫。这可能吗？

编辑:让我更彻底地描述一下我的问题:我可以在不执行some_function 的情况下获取字符串“some_prvilege”吗？像这样的东西:

a = getattr(module, 'somefunction')
print a.decorator_arguments

?感谢您到目前为止对我的帮助!

Answer 1

你的装饰器基本上检查用户是否有执行给定功能的权限，我实际上不明白你为什么要检索(附加)被包装的功能的权限，但你可以在不添加的情况下执行此操作所有函数的另一个参数。

def needs_privilege(privilege, project=None):
    """Check whether the logged-in user is authorised based on the
    given privilege

    @type privilege: Privilege object, id, or str
    @param privilege: The requested privilege"""

    def validate(func, self, *args, **kwargs):
        """Validator of needs_privillige"""
        try: check(self.user, privilege, project)
        except AccessDenied:
            return abort(status_code=401)
        else:
            return func(self, *args, **kwargs)
    validate.privelege = privelege
    return decorator(validate)

顺便说一句，你的装饰器应该是这样的:

def needs_privilege(privilege, project=None):
    def validate(func):
        def new_func(self, *args, **kwargs):
            try: 
                check(self.user, privilege, project)
            except AccessDenied:
                return abort(status_code=401)
            else:
                return func(self, *args, **kwargs)
        new_func.privilege = privilege
        return new_func
    return validate