python - 将 CURL 命令行转换为 Python 脚本

Question

在 python 脚本中使这个 cmd 行 curl 语句工作太麻烦了...帮助!正在尝试使用 URLLIB。

curl -X POST "http://api.postmarkapp.com/email"\
-H“接受:应用程序/json”\
-H "Content-Type: application/json"\
-H "X-Postmark-Server-Token: abcdef-1234-46cc-b2ab-38e3a208ab2b"\
-v\
-d "{From: 'sender@email.com', To: 'recipient@email.com', Subject: 'Postmark test', HtmlBody: 'Hello dear Postmark user.'}"

Answer 1

好的，所以您可能应该使用 urllib2 来提交实际请求，但这是代码:

import urllib
import urllib2

url = "http://api.postmarkapp.com/email"
data = "{From: 'sender@email.com', To: 'recipient@email.com', Subject:   'Postmark test', HtmlBody: 'Hello dear Postmark user.'}"
headers = { "Accept" : "application/json",
        "Conthent-Type": "application/json",
        "X-Postmark-Server-Token": "abcdef-1234-46cc-b2ab-38e3a208ab2b"}
req = urllib2.Request(url, data, headers)
response = urllib2.urlopen(req)
the_page = response.read()

checkout :urllib2 the unwritten manual

我收到 401 未经授权的响应，所以我猜它有效:)