Python/Django 迭代一个列表，同时检查对象内部

Question

以下伪代码最简洁的方法是什么？

class Player
   id
   name

class Participant  (is a subset of Player with an added status)
   player_id (ForeignKey to Player)
   status

所以你可以有一个玩家列表(Wayne、Chuck、Bobby)然后是参与者列表(韦恩(状态:是)，鲍比(状态:否))请注意，Chuck 不在参与者列表中。

因此，我正在遍历所有 Player，如果 Participant 存在则输出状态。

player_list = list with Player objects
participant_list = list with Participant objects

for player in player_list:
   if player.id exists in participant_list //QUESTION IS HERE: HOW DO I DO THIS???
         print participant.status

我不确定如何检查包含对象的列表的内部 ID？？？

Answer 1

加入另一个循环

player_list = list with Player objects
participant_list = list with Participant objects

for player in player_list:
    for participant in participant_list:
        if player == participant.player:
            print participant.status
            break

不是最漂亮的解决方案，但很简单。