c# - 绘制多个矩形c#

Question

在 C# 中绘制 25 个矩形 (5*5) 的最佳方法是什么？我稍后需要能够到达特定的矩形并更改其颜色，例如，如果用户输入了错误的词，则将颜色更改为红色。在这种情况下创建一个矩形数组会更合适吗？

这是我目前的情况

Graphics g = pictureBox1.CreateGraphics();

int x =0;
int y= 0;
int width = 20;
int height = 20;
for (int i = 0; i < 25; i++)
{
    if (i <= 4)
    {
        g.FillRectangle(Brushes.Blue, x, y, width, height);
        x += 50;
    }
    else if (i > 4)
    {
        y = 50;
        g.FillRectangle(Brushes.Blue, x, y, width, height);
        x += 50;
    }
}

Answer 1

这应该让您入门，而不是完整的代码。您将需要添加一个 PictureBox 控件并使用默认名称 (picurebox1)。编辑:也需要添加一个按钮 :)

public partial class Form1 : Form
{
    public List<Rectangle> listRec = new List<Rectangle>();
    Graphics g;

    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        Rectangle rect = new Rectangle();
        rect.Size = new Size(100,20);
        for (int x = 0; x < 5; x++)
        {
            rect.X = x * rect.Width;
            for (int y = 0; y < 5; y++)
            {
                rect.Y = y * rect.Height;
                listRec.Add(rect);
            }
        }

        foreach (Rectangle rec in listRec)
        {
            g = pictureBox1.CreateGraphics();
            Pen p = new Pen(Color.Blue);
            g.DrawRectangle(p, rec);
        }
    }

    public void ChangeColor(Rectangle target, Color targetColor)
    {
        Pen p = new Pen(targetColor);
        g.DrawRectangle(p, target.X, target.Y, target.Width, target.Height);
    }

    private void Form1_KeyDown(object sender, KeyEventArgs e)
    {
        switch (e.KeyCode)
        {
            case Keys.D0: ChangeColor(listRec[0], Color.Red);
                break;
            case Keys.D1: ChangeColor(listRec[1], Color.Red);
                break;
            //..more code to handle all keys..
        }
    }    
}