两个日期之间的 Android 通话记录数据和来自同一号码的通话总时长。

Question

想要获取今天、昨天、过去 7 天和过去 30 天的通话记录历史记录，同时我想显示该特定号码的来电和去电的总持续时间。

假设 abc 有 3 个去电和 1 个来电。我应该得到这些电话的总持续时间。

如果我们可以通过游标 GroupBy 或 ORDER BY 子句而不是循环和添加持续时间来获取持续时间和调用日志，请告诉我。给我粗略的结构以获得更好的解决方案并且可以有效地工作。

         String[] whereValue=null;
        Calendar calendar = Calendar.getInstance();
        String currentDate = String.valueOf(calendar.getTimeInMillis());
        switch (period) {
            case DAY:
                whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            case YESTERDAY:
                whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            case WEEK:
                whereValue  = new String[]{getTimeFrom(period),currentDate};

                break;
            case MONTH:
                    whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            default:
                Log.d(Utils.LOG_TAG, "Error:");
        }
        String strOrder = android.provider.CallLog.Calls.DATE + " DESC";
        Uri callUri = Uri.parse("content://call_log/calls");

        Cursor cur = context.getContentResolver().query(callUri, null, android.provider.CallLog.Calls.DATE+" BETWEEN ? AND ?", whereValue, strOrder);

   String callNumber = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.NUMBER));

            String callName = cur
                    .getString(cur
                            .getColumnIndex(android.provider.CallLog.Calls.CACHED_NAME));
      String callType = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.TYPE));
            String dir = null;
            int dircode = Integer.parseInt(callType);
            switch (dircode) {
                case CallLog.Calls.OUTGOING_TYPE:
                case CallLog.Calls.INCOMING_TYPE:
                    break;

            }
            String duration = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.DURATION));

以上代码甚至无法获取从日期到日期之间的通话记录。有帮助吗？

Answer 1

我已经设法获取了两个日期之间的通话记录。您可以获得今天、昨天、过去 7 天、过去 30 天的通话记录。以及通话时长(也有多次来自同一号码的电话)

你应该通过选择作为
android.provider.CallLog.Calls.DATE + "BETWEEN ? AND ?"和

选择参数

whereValue = new String[]{String.valueOf(calendar1.getTimeInMillis()),String.valueOf(calendar.getTimeInMillis());};

  Map<String, StatEntry> callLogMap1 = new HashMap<>();
            callLogMap1.clear();

            String strOrder1 = android.provider.CallLog.Calls.DATE + " DESC limit 500";

            Uri callUri = Uri.parse("content://call_log/calls");
            Cursor cur = getContentResolver().query(CallLog.Calls.CONTENT_URI, null, android.provider.CallLog.Calls.DATE + " BETWEEN ? AND ?", whereValue,
                    strOrder1);


            if (cur != null) {
                try {
                    while (cur.moveToNext()) {

                        String callNumber = cur.getString(cur.getColumnIndex(android.provider.CallLog.Calls.NUMBER));
                        //    String callDate = cur.getString(cur.getColumnIndex(android.provider.CallLog.Calls.DATE));
                        int duration = cur.getInt(cur.getColumnIndex(android.provider.CallLog.Calls.DURATION));

                        String name = cur.getString(cur.getColumnIndex(CallLog.Calls.CACHED_NAME));

                        StatEntry StatEntry1 = null;

                        int id = cur.getInt(cur.getColumnIndex(CallLog.Calls._ID));

                        int type = cur.getInt(cur.getColumnIndex(CallLog.Calls.TYPE));

                        if (callNumber != null & duration > 0 && (type == 1 || type == 2)) {

                            int n = callNumber.length();
                            String lastDigits;
String number = callNumber.replaceAll(Pattern.quote("+"), ""); //replacing the plus
    //am just checking last 5digitis and saving to map so that we can get same //number duration
                            if (n >= 5) {

                                try {

                                    lastDigits = String.valueOf(Long.parseLong(number) % 100000);
                                } catch (NumberFormatException e) {
                                    e.printStackTrace();
                                    lastDigits = callNumber;
                                }
                            } else {
                                lastDigits = callNumber;
                            }

                            if (callLogMap1.containsKey(lastDigits)) {
                                StatEntry1 = callLogMap1.get(callNumber);

                                    StatEntry1.setTitle(callNumber);
                                StatEntry1.Duration += duration;


                            } else {
                                StatEntry1 = new StatEntry();

                  StatEntry1.setTitle(callNumber);

      StatEntry1.Duration += duration;
                           }


                    StatEntry1.setTime((StatEntry1.Duration) / 60);


                            callLogMap1.put(callNumber, StatEntry1);


                        }
                    }

                } catch (Exception e) {
                    e.printStackTrace(

                    );
                } finally {
                    cur.close();
                }
            }

最后将 hashmap 数据传递给 arraylist。

ArrayList<StatEntry> callLogList1 = new ArrayList<>(callLogMap1.size());

        if (callLogMap1.size() > 0) {
            for (Map.Entry<String, StatEntry> entry : callLogMap1.entrySet()) {
                callLogList1.add(entry.getValue());


            }
        }

希望这对观众有所帮助。