Python - 从字符串中删除停用词

Question

我在创建从字符串输入中删除停用词的代码时遇到问题。目前，这是我的代码:

stopWords = [ "a", "i", "it", "am", "at", "on", "in", "to", "too", "very", \
                 "of", "from", "here", "even", "the", "but", "and", "is", "my", \
                 "them", "then", "this", "that", "than", "though", "so", "are" ]
stemEndings = [ "-s", "-es", "-ed", "-er", "-ly" "-ing", "-'s", "-s'" ]
punctuation = [ ".", ",", ":", ";", "!", "?" ]
line = raw_input ("Type in lines, finish with a . at start of line only:")
while line != ".":
    def remove_punctuation(input): #removes punctuation from input
        output = ""
        text= 0
        while text<=(len(input)-1) :
            if input[text] not in punctuation:
               output=output + input[text]
            text+=1
        return output
    newline= remove_punctuation(line)
    newline= newline.lower()

可以添加什么代码来根据上面的停用词列表从字符串中删除停用词？提前谢谢你。

Answer 1

正如格雷格所建议的，您应该使用 for循环而不是 while因为它更像 pythonic 且易于理解代码。此外，您应该在 while 之前声明您的函数。循环输入，这样 python 解释器就不会每次都重新定义函数!

此外，如果需要，您可以将标点符号设置为 string而不是 list (为了可读性和易用性)

stopWords = [ "a", "i", "it", "am", "at", "on", "in", "to", "too", "very", \
              "of", "from", "here", "even", "the", "but", "and", "is", "my", \
              "them", "then", "this", "that", "than", "though", "so", "are" ]
stemEndings = [ "-s", "-es", "-ed", "-er", "-ly" "-ing", "-'s", "-s'" ]
punctuation = ".,:;!?"

def remove_punctuation(input_string):
    for item in punctuation:
        input_string = input_string.replace(item, '')
    return input_string

line = raw_input ("Type in lines, finish with a . at start of line only:")

while not line == ".":
    newline = remove_punctuation(line)
    newline = newline.lower()